错哪了

[木可大大]

Problem Description
Your task is to Calculate the sum of some integers.

Input
Input contains multiple test cases. Each test case contains a integer N, and then N integers follow in the same line. A test case starting with 0 terminates the input and this test case is not to be processed.

Output
For each group of input integers you should output their sum in one line, and with one line of output for each line in input.

Sample Input
4 1 2 3 4
5 1 2 3 4 5
0

Sample Output
10
15
我的代码是
#include <stdio.h>
#include<stdlib.h>
int main()
{
int n,temp=0,sum=0;
scanf("%d",&n);
while(n--)
{
scanf("%d",&temp);
while(temp)
{
sum+=temp;
printf("%d\n",sum);

}
}
return 0;
}
错哪了？

[alfredsue]

while(temp)
{
sum+=temp;
printf("%d\n",sum);

}
你这循环是什么意思？这个循环能出去么？

[luxiaoxun]

you should output their sum in one line, and with one line of output for each line in input.
输出不符合要求

[terminatorbin]

#include <stdio.h> 
#include <stdlib.h> 
int main() 
{ 
    int n,temp=0,sum=0; 
    scanf("%d",&n); 
    while(n--) 
    { 
      scanf("%d",&temp); 
/*这里的while循环是一个死循环，如果输入一个不为0的数时，就不断的执行下去！由于temp的值没有改变，所以跳不出这个循环，导致出错*/
      while(temp) 
  { 
sum+=temp; 
printf("%d\n",sum); 

  } 

} 
return 0; 
} 

楼主，应该学会一下怎么样调试程序才行，编程容易，查错、调试才难啊！
别外，不是很明白，你这道题的目的是什么！
可以，讲訹一下，程序要实现什么功能吗？

[xiansizhe]

只答题不结贴..

[oo_v_oo]

[Quote=引用 3 楼 bargio_susie 的回复:]
这样行不行？


C/C++ code#include <stdio.h>

int main()
{
int n,temp=0,sum=0;
int a[1024];
int i = 0 ,j;

while(1)
{
scanf("%d", &n);
if (n == 0)
{
printf("\noutput\n");
for(j=0; j<i; j++)
printf("%d\n", a[j]);
break;
}
while(n--)
{
sc…
[/Quote]

[Teaerror]

用TC编译是没有错的，但别说第2个循环是个死循环了，如果你输入的n是个负数，也是死循环。

[mifeixq]

经过测试，下面代码AC

#include <stdio.h>

int main()
{
	while(1)
	{
		int n,temp=0,sum=0;
		scanf("%d",&n);
		if(!n)
			break;
		while(n--)
		{
			scanf("%d", &temp);
			sum+=temp;
		}
		printf("%d\n", sum);
	}
	return 0;
}

[青葱岁月不可追]

貌似之前见过这个帖子

[ForestDB]

#include <stdio.h>

int main(void)
{
  int i, j, k, s;

  while(1)
  {
    scanf("%d", &i);
    if(i == 0)
      break;
    s = 0;
    for(j = 0; j < i; ++j)
    {
      scanf("%d", &k);
      s += k;
    }
    printf("%d\n", s);
  }

  return 0;
}

[devil_zuiai]

while(temp)
{
sum+=temp;
printf("%d\n",sum);

}
这是一个死循环

[bargio_susie]

这样行不行？

#include <stdio.h>

int main() 
{ 
	int n,temp=0,sum=0; 
	int a[1024];
	int i = 0 ,j;

    while(1) 
    { 
		scanf("%d", &n);
		if (n == 0)
		{
			printf("\noutput\n");
			for(j=0; j<i; j++)
				printf("%d\n", a[j]);
			break;
		}
		while(n--) 
		{ 
			scanf("%d", &temp); 
			sum += temp;  
		} 
		a[i++] = sum;
		sum = 0;
	} 

	return 0; 
}