*****如何将字符串变量转化为整型变量

[yunhaitian]

char a[]="50";
现在我想在字符串变量a在循环中每次增1，如何做到？请各位大虾指点一二

[yunhaitian]

急需帮助，诸位帮帮忙呀

[rusan]

int b=0;
...
b = atoi(a);
b++;
a = itoa(b);
...

[SCUM]

比较标准的方法：

short count;
char count_str[]="00000";

...
count++;
...
itoa( count, count_str, 10 );
...
.............

[the_lion]

#include <stdlib.h>


int i;
char a[]="50";
int urnumber=100;//just a presumption
for(i=50;i<100;i++)
{
int b=i;
a=_itoa(b,a,10);//10 is the Base_of_Value
cout<<"The current value of a[] is:"<<a<<endl;
}

[djhdu]

sprintf(a,"%d",atoi(a)+1)

[yhp]

#include <stdlib.h>
#include <iostream.h>
void main()
{
int i;
char a[]={50};
for(i=50;i<100;i++)
{
int b=i;
itoa(b,a,10);
cout<<"The Current a[] is :"<<a<<endl;
}
}

[jkaikai]

sprintf(a,"%d",++atoi(a))