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如何将不同条件的group by放到一个select里面？
表
c1 n1
------
b 1
b 2
c 1
c 2
c 3
c 4
我想得到下面的结果，根据c1 group by,符合c1='c',列2是count(*),列3是符合条件c1='c'并且n1>2的count(*),一个select显示出来，最好不要用union。
结果：
c1 sum1 sum2
--------------
c 4 2
c1 n1
------
b 1
b 2
c 1
c 2
c 3
c 4
我想得到下面的结果，根据c1 group by,符合c1='c',列2是count(*),列3是符合条件c1='c'并且n1>2的count(*),一个select显示出来，最好不要用union。
结果：
c1 sum1 sum2
--------------
c 4 2
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taler 2003-06-13
是的，Lastdrop(空杯)的方法最容易理解
oraclenewbie 2003-06-13
偶刚学oracle，看起来Lastdrop(空杯)的最好了，其他的偶都看不懂，是不是这样的？
Lastdrop 2003-06-13
select c1, count(*) sum1, sum(decode(sign(n1-2),1,1,0)) sum2
from yourtable
where c1='c'
group by c1
from yourtable
where c1='c'
group by c1
things 2003-06-12
select c.c1, max(a.b), max(b.c) from
(select c1, count(*) b from table1 group by c1) a,
(select c1, count(*) c from table1 where nl>2 group by c1) b,
table1 c
where a.c1(+)=c.c1 and b.c1(+)=c.c1
(select c1, count(*) b from table1 group by c1) a,
(select c1, count(*) c from table1 where nl>2 group by c1) b,
table1 c
where a.c1(+)=c.c1 and b.c1(+)=c.c1
BlueskyWide 2003-06-12
select tab1.aa,tab1.bb,tab2.dd from
(select c1 aa,count(*) bb from your_table group by c1) tab1,
(select c1 cc,count(*) dd from your_table where nl>2 group by c1) tab2
where tab1.aa=tab2.cc;
(select c1 aa,count(*) bb from your_table group by c1) tab1,
(select c1 cc,count(*) dd from your_table where nl>2 group by c1) tab2
where tab1.aa=tab2.cc;
jiezhi 2003-06-12
select c1,(select count(*) from a where c1='c') sum1,
(select count(*) from a where c1='c' and n1>2) sum2
from a where c1='c'
(select count(*) from a where c1='c' and n1>2) sum2
from a where c1='c'