这个式子有解吗?
求ijk + kji = 1333 的i , j , k的程序i、j、k是1位的整数。
我的程序如下:
#include <iostream.h>
void main ()
{
int i = 1;
int j = 0;
int k = 1;
for (; i <= 9; i++)
for (; j <= 9; j++)
for (; k <= 9; k++)
if ((101 * (i + k) + 20 * j) == 1333)
{
break;
}
if (i == 10 && j == 10 && k == 10)
{
cout << "无解" << endl;
return;
}
cout << "i = " << i << endl;
cout << "j = " << j << endl;
cout << "k = " << k << endl;
cin.get ();
return;
}
但是显示 无解,