下面的问题如何解

[xiao_xiao_zi]

判断学生成绩的优劣。用户输入分数，小于60分不及格，60 = < 并且 < 75及格, 75 = < 并且 < 90良好，90 <= 并且
<= 100 优秀。 要求程序中不得出现if、else、while、for、switch关健字，不得使用任何判断、循环语句、不得嵌入汇编

请给个思路！？

[brookmill]

自己写一个grade[]数组
printf("%s\n", grade[score / 15]);

[brookmill]

char grade[] =
{
"不及格",
"不及格",
"不及格",
"不及格",
"及格",
"良好",
"优秀",
};

[brookmill]

唉，又错了。应该是
char * grade[] =

[mstlq]

好无聊……

#include <stdio.h>
#include <stdlib.h>

char rank[4][10]={"不及格","及格","良好","优秀"};
unsigned char level[101]=  {0,0,0,0,0,0,0,0,0,0,
                            0,0,0,0,0,0,0,0,0,0,
                            0,0,0,0,0,0,0,0,0,0,
                            0,0,0,0,0,0,0,0,0,0,
                            0,0,0,0,0,0,0,0,0,0,
                            0,0,0,0,0,0,0,0,0,0,
                            0,1,1,1,1,1,1,1,1,1,
                            1,1,1,1,1,2,2,2,2,2,
                            2,2,2,2,2,2,2,2,2,2,
                            3,3,3,3,3,3,3,3,3,3,
                            3};

int main()
{
   int mark;
   scanf("%d",&mark);
   puts(rank[level[mark]]);
}

[aozhi]

main()
{
int mark;
scanf("%d",&mark);
printf(mark<60?"不及格":(mark<75?"及格":(mark<90?"良好":"优秀")));
}

[aozhi]

哦，不能判断。

[love_route]

1楼的方法比较简洁

[aozhi]

static char band[4][]={"不及格","及格","良好","优秀"};

int main()
{
int mark;
int i=0;

scanf("%d",&mark);
i=mark/60+mark/75+mark/90;
printf(band[i]);
}

[bobo45123]

int main()
{
float score = 0;
int num = 0;
int info[][10] = {"不及格","不及格","不及格","不及格","及格","良好","优秀"};

printf("please input the score:");
scanf("%f", score);

num = (int)float/15;
printf("the score is:%s\n", info[num]);

return 0;
}

不过对于成绩的输入数据的合法性无法进行处理

[aozhi]

自评一下。（胡说八道，不要脸一次）
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