将数据保存到数组

[wxdcxp]

00 00 01 F4  00 00 01 F9  00 00 01 F4  00 00 01 F4 
00 00 01 FE  00 00 01 F4  00 00 01 F4  00 00 01 F9 
00 00 01 F4  00 00 01 F4  00 00 01 FE  00 00 01 F4 
00 00 01 F4  00 00 01 F9  00 00 01 F4  00 00 01 F4 
00 00 01 FE  00 00 01 F4  00 00 01 F4  00 00 01 F9 
00 00 01 F4  00 00 01 F4  00 00 01 FE  00 00 00 00 
00 00 00 00  00 00 02 44  00 00 02 44  00 00 02 44 
00 00 01 B8  00 00 01 B8  00 00 01 B8  00 00 02 44 
00 00 01 B8  00 00 02 44  00 00 01 B8  00 00 02 44 
00 00 01 B8  00 00 02 44  00 00 01 B8  00 00 00 00 
00 00 00 00  00 00 00 02  00 00 00 73  00 00 00 A3 
FF FF FF FD  00 00 00 75  00 00 00 7F  FF FF FF FD 
00 00 00 75  00 00 00 7F  00 00 00 00  00 00 00 00 
00 00 06 F6  00 00 07 E0  00 00 06 F4  00 00 02 16 
00 00 02 12  00 00 02 1B  00 00 00 80  00 00 00 80 
00 00 00 80  00 00 00 00  00 00 00 00  00 00 00 00 
00 00 06 F6  00 00 07 E0  00 00 06 F4  00 00 02 16 
00 00 02 12  00 00 02 1B  00 00 00 80  00 00 00 80 
00 00 00 80  00 00 00 00  00 00 00 00  00 00 00 00 
00 00 06 F6  00 00 07 E0  00 00 06 F4  00 00 02 16 

最近在做一个自动读取EEPROM数据的Tool，以上是部分EEPROM的数据
如何将以上数据保存到一个二维数组里？

[昵称很不好取]

只针对你给的数据，如果数据行数与列数会变，可以通过移动文件指针进行判断，进而分配数组大小

#include <stdio.h> 
#include <stdlib.h> 

int main (void) { 
	FILE *fp=NULL;
	int i=0;
	char a[20][52];
	fp = fopen("C:\\1.txt","r");
	if(!fp){
		printf("Error\n");
		exit(0);
	}
	for(i=0; i<20; i++){
		fgets(a[i],51,fp);
	}

	for(i=0; i<20; i++){
		printf("%s",a[i]);
	}

	fclose(fp);

	return 0; 
} 

[cattycat]

EEPROM是什么，你的数据是二进制的？如果是二进制的话，直接定义int的二维数组，每一行可以当成有4个int元素，行数就是你共有多少行。

[wxdcxp]

忘记说明了，需要的数据不能包含空格

[wxdcxp]

例如a[0][0]里的内容是"00"
a[2][0]里的内容是"01"

[ZXW0521]

每次读2个字符，转成数字，存到一个单元里，
循环做就可以了，

有点没弄清楚lz的意思

[ZXW0521]

如果源是字符串类型的，

char buf[] = {.......}; //那些要读的东西
char tmp[3];

int result[40][16];//不一定是40行，假设是40行
memset(result, 0, 40*16*sizeof(int));
for (int i = 0; i < 40; i++)
{
for (int j = 0; j < 16; i++)
{
tmp[0] = buf[(i*16+j)*2];
tmp[1] = buf[(i*16+j)*2 + 1];
tmp[2] = 0;

result[i][j] = atoi(tmp);
}
}