问一个分组的问题

[rottenapple]

销售表A,有字段sale_date, employee_id,client_id,product_id,内容如下

20100302 001 C1 P1
20100302 001 C1 P2
20100302 002 C1 P1
20100302 002 C2 P1
20100302 002 C2 P2
20100302 003 C1 P1

现在需要把一天中，一个销售人员对一个客户卖出两种以上货物的纪录打印出来，如何实现？结果如下：
20100302 001 C1 P1
20100302 001 C1 P2
20100302 002 C2 P1
20100302 002 C2 P2

[ypfe23]

select * from (
select sale_date,
employee_id,
client_id,
product_id,
count(1) over(partition by sale_date, employee_id, client_id) as cn
from a) where cn>1
前提是一个人卖一个客户一个产品两件的话，在库里存储要有数量

[ngx20080110]

with tmp as (
select to_date('20100302','yyyymmdd') sale_date, '001' employee_id, 'C1' client_id, 'P1' product_id from dual
union all
select to_date('20100302','yyyymmdd') sale_date, '001' employee_id, 'C1' client_id, 'P2' product_id from dual
union all
select to_date('20100302','yyyymmdd') sale_date, '002' employee_id, 'C1' client_id, 'P1' product_id from dual
union all
select to_date('20100302','yyyymmdd') sale_date, '002' employee_id, 'C2' client_id, 'P1' product_id from dual
union all
select to_date('20100302','yyyymmdd') sale_date, '002' employee_id, 'C2' client_id, 'P2' product_id from dual
union all
select to_date('20100302','yyyymmdd') sale_date, '002' employee_id, 'C1' client_id, 'P1' product_id from dual
) 
select mt.sale_date,mt.employee_id,mt.client_id,mt.product_id
from tmp mt,(
select sale_date,employee_id,client_id,count(distinct product_id)
from tmp
group by sale_date,employee_id,client_id
having count(distinct product_id) > 1
) st
where mt.sale_date = st.sale_date
and mt.employee_id = st.employee_id
and mt.client_id = st.client_id;

[iqlife]

select *
from A
where (sale_date, employee_id,client_id) in
(select sale_date, employee_id,client_id
from A
group by sale_date, employee_id,client_id
having count(*)>1)

[Leoyang_FarAwayFrom]

分区查？over是什么意思？

不懂，帮顶 我也想知道如何弄...

[碧水幽幽泉]

1.2.3楼都对！
但是1楼好！效率要高些！

[luoyoumou]

create table a(
sale_date date,
employee_id char(4),
client_id char(4),
product_id char(4)
);

insert into a(sale_date,employee_id,client_id, product_id) values(to_date('20100302','yyyymmdd'), '001', 'C1', 'P1');
insert into a(sale_date,employee_id,client_id, product_id) values(to_date('20100302','yyyymmdd'), '001', 'C1', 'P2');
insert into a(sale_date,employee_id,client_id, product_id) values(to_date('20100302','yyyymmdd'), '002', 'C1', 'P1');
insert into a(sale_date,employee_id,client_id, product_id) values(to_date('20100302','yyyymmdd'), '002', 'C2', 'P1');
insert into a(sale_date,employee_id,client_id, product_id) values(to_date('20100302','yyyymmdd'), '002', 'C2', 'P2');
insert into a(sale_date,employee_id,client_id, product_id) values(to_date('20100302','yyyymmdd'), '002', 'C1', 'P1');

SELECT to_char(a1.sale_date,'yyyymmdd'), a1.employee_id, a1.client_id, a1.product_id, count(a1.product_id) product_count
FROM a a1
GROUP BY to_char(a1.sale_date,'yyyymmdd'), a1.employee_id, a1.client_id, a1.product_id
HAVING COUNT(a1.product_id)>=2;

[心中的彩虹]

SQL> edi
已写入 file afiedt.buf

  1  select to_char(sale_date,'yyyymmdd') sale_date,employee_id,client_id,product_id from
  2  tb a where exists(select 1 from tb where employee_id=a.employee_id and client_id=a.client_id
  3  group by employee_id,client_id
  4* having count(1)>=2)
SQL> /

SALE_DAT EMPLO CLIEN PRODU
-------- ----- ----- -----
20100302 001   c1    p1
20100302 001   c1    p2
20100302 002   c2    p1
20100302 002   c2    p2

[luoyoumou]

CREATE TABLE a(
sale_date   DATE,
employee_id CHAR(4),
client_id   CHAR(4),
product_id  CHAR(4)
);

INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '001', 'C1', 'P1');
INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '001', 'C1', 'P2');
INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '002', 'C1', 'P1');
INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '002', 'C2', 'P1');
INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '002', 'C2', 'P2');
INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '002', 'C1', 'P1');

SELECT to_char(a1.sale_date,'yyyymmdd'), a1.employee_id, a1.client_id, a1.product_id
FROM a a1
WHERE EXISTS (SELECT to_char(a2.sale_date,'yyyymmdd'), a2.employee_id, a2.client_id
              FROM a a2
	      WHERE to_char(a2.sale_date,'yyyymmdd')=to_char(a1.sale_date,'yyyymmdd')
	      AND  a2.employee_id= a1.employee_id
	      AND a2.client_id=a1.client_id
	      GROUP BY to_char(a2.sale_date,'yyyymmdd'), a2.employee_id, a2.client_id
	      HAVING COUNT(DISTINCT a2.product_id)>=2 );

[luoyoumou]

CREATE TABLE a(
sale_date   DATE,
employee_id CHAR(4),
client_id   CHAR(4),
product_id  CHAR(4)
);

INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '001', 'C1', 'P1');
INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '001', 'C1', 'P2');
INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '002', 'C1', 'P1');
INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '002', 'C2', 'P1');
INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '002', 'C2', 'P2');
INSERT INTO a(sale_date,employee_id,client_id, product_id) VALUES(to_date('20100302','yyyymmdd'), '002', 'C1', 'P1');

SELECT to_char(a1.sale_date,'yyyymmdd'), a1.employee_id, a1.client_id, a1.product_id
FROM a a1
WHERE EXISTS (SELECT 1
              FROM a a2
	      WHERE to_char(a2.sale_date,'yyyymmdd')=to_char(a1.sale_date,'yyyymmdd')
	      AND  a2.employee_id= a1.employee_id
	      AND a2.client_id=a1.client_id
	      GROUP BY to_char(a2.sale_date,'yyyymmdd'), a2.employee_id, a2.client_id
	      HAVING COUNT(DISTINCT a2.product_id)>=2 );

-- 我是来蹭分的！

[luoyoumou]

-- 请注意：两种以上货物

-- 是“两种”，而不是“两件”！

[yangant]

select sale_date, employee_id,client_id,product_id from A where exists (
select * from A as B where B.sale_date=A.sale_date and
B.employee_id=A.employee_id and B.client_id=A.client_id and
B.product_id<>A.product_id
)

[bbbbbb888888]

1L的正点

[wjz748305545]

接分ing

[清风智语]

select sale_date, employee_id,client_id,product_id,
from tb a
where exists
   (select 1 from tb b where b.employee_id = a.employee_id
     and a.client_id = b.client_id
     group by sale_date,employee_id
     having count(1)>=2);

[codearts]

看了下，楼主是说2种，不是2件。

所以having count(1) 这种写法是不对的，

having count(disintct product_id) 这种写法才对。

[tangren]

--练习一下
--1.
with tt as (
  select date'2010-03-02' sale_date, '001' employee_id, 'C1' client_id, 'P1' product_id from dual union all
  select date'2010-03-02' sale_date, '001' employee_id, 'C1' client_id, 'P2' product_id from dual union all
  select date'2010-03-02' sale_date, '002' employee_id, 'C1' client_id, 'P1' product_id from dual union all
  select date'2010-03-02' sale_date, '002' employee_id, 'C2' client_id, 'P1' product_id from dual union all
  select date'2010-03-02' sale_date, '002' employee_id, 'C2' client_id, 'P2' product_id from dual union all
  select date'2010-03-02' sale_date, '002' employee_id, 'C1' client_id, 'P1' product_id from dual
  ) 
SELECT sale_date, employee_id, client_id, product_id
  FROM (SELECT a.*, COUNT(1) over(PARTITION BY sale_date, employee_id, client_id) cn
          FROM (SELECT DISTINCT sale_date, employee_id, client_id, product_id FROM tt) a)
 WHERE cn > 1;
--2.
with tt as (
  select date'2010-03-02' sale_date, '001' employee_id, 'C1' client_id, 'P1' product_id from dual union all
  select date'2010-03-02' sale_date, '001' employee_id, 'C1' client_id, 'P2' product_id from dual union all
  select date'2010-03-02' sale_date, '002' employee_id, 'C1' client_id, 'P1' product_id from dual union all
  select date'2010-03-02' sale_date, '002' employee_id, 'C2' client_id, 'P1' product_id from dual union all
  select date'2010-03-02' sale_date, '002' employee_id, 'C2' client_id, 'P2' product_id from dual union all
  select date'2010-03-02' sale_date, '002' employee_id, 'C1' client_id, 'P1' product_id from dual
  ) 
SELECT a.*
  FROM tt a,
       (SELECT sale_date, employee_id, client_id
          FROM (SELECT DISTINCT sale_date, employee_id, client_id, product_id FROM tt)
         GROUP BY sale_date, employee_id, client_id
        HAVING COUNT(1) > 1) b
 WHERE a.sale_date = b.sale_date AND
       a.employee_id = b.employee_id AND
       a.client_id = b.client_id;