求一个m字符串mac地址转换成十六进制的函数

[oolhyzcx]

例如我取得一个00:FF:0A:0C:06:03的MAC地址，我想把它转换成0x00,0xFF,0x0A,0x0C,0x06,0x03的十六进制，存在数组中，我是为了写ARP包。

[jernymy]

#include "stdio.h"
#include "string.h"

#define MAX_LEN   128

static unsigned char SwitchChar(char chStr)
{
	if (chStr >= '0' && chStr <= '9')
	{
		return (chStr - '0');
	}
	else if (chStr >= 'A' && chStr <= 'f')
	{
		return (chStr - 'A' + 10);
	}
	else if (chStr >= 'a' && chStr <= 'f')
	{
		return (chStr - 'a' + 10);
	}
	else
	{
		return 0;
	}
}

int main(void)
{
    char achSrc[] = "00:FF:0A:0C:06:03";
	unsigned char abyDst[MAX_LEN+1] = {0};
    char *pchStr = strtok(achSrc, ":");
	int  nIdx = 0;
	int  nTotal = 0;

    while (NULL != pchStr)
    {
		abyDst[nTotal++] = (SwitchChar(*pchStr) << 4) | SwitchChar(*(pchStr+1));
        //保存n
        pchStr = strtok(NULL, ":");
    }

	for (nIdx = 0; nIdx < nTotal; nIdx++)
	{
		printf("0x%x:", abyDst[nIdx]);
	}

	return 0;
}

[jernymy]

/*
例如我取得一个00:FF:0A:0C:06:03的MAC地址，
我想把它转换成0x00,0xFF,0x0A,0x0C,0x06,0x03的
十六进制，存在数组中，我是为了写ARP包。
*/

#include "stdio.h"
#include "string.h"

#define MAX_LEN   128

static unsigned char SwitchChar(char chStr)
{
	if (chStr >= '0' && chStr <= '9')
	{
		return (chStr - '0');
	}
	else if (chStr >= 'A' && chStr <= 'F')
	{
		return (chStr - 'A' + 10);
	}
	else if (chStr >= 'a' && chStr <= 'f')
	{
		return (chStr - 'a' + 10);
	}
	else
	{
		return 0;
	}
}

int main(void)
{
    char achSrc[] = "00:FF:0A:0C:06:03";
	unsigned char abyDst[MAX_LEN+1] = {0};
    char *pchStr = NULL;
	int  nIdx = 0;
	int  nTotal = 0;
	
	printf("Src Str: %s\n", achSrc);
	pchStr = strtok(achSrc, ":");
	while (NULL != pchStr)
    {
		abyDst[nTotal++] = (SwitchChar(*pchStr) << 4) | SwitchChar(*(pchStr+1));
        //保存n
        pchStr = strtok(NULL, ":");
    }
	
	printf("Dst Str: ");
	for (nIdx = 0; nIdx < nTotal; nIdx++)
	{
		printf("0x%02X:", abyDst[nIdx]);
	}
	printf("\n");
	
	return 0;
}

[oolhyzcx]

输出0x00的形式没用，关键是在数组中存的就是0x00的形式，上面那位大虾的功能我都实现了，去掉了：，并且可以用 printf("0x%x:", m[i]);输出0x00的形式

[oolhyzcx]

我现在数组中已经是存的00 FF 0A 0C 06 03这种形式，就是不会在前面加0x，转换成0x00的形式

[赵4老师]

char achSrc[] = "00:FF:0A:0C:06:03";
unsigned char abyDst[6];
sscanf(achSrc,"%02x:%02x:%02x:%02x:%02x:%02x",&abyDst[0],&abyDst[1],&abyDst[2],&abyDst[3],&abyDst[4],&abyDst[5])

[oolhyzcx]

不正确啊，输出来的都不对

[白云飘飘飘]

char buff[]="00:FF:0A:0C:06:03";
char *p=strtok(buff,":");
char out[10]="0x";
while(p!=0)
{

int n;
sscanf(p,"%x",&n);
strcat(out,p);
printf("%s\n",out);
p=strtok(NULL,":");
}

[白云飘飘飘]

char buff[]="00:FF:0A:0C:06:03";
char *p=strtok(buff,":");
char out[10]="0x";
while(p!=0)
{

int n;
sscanf(p,"%x",&n);
strcat(out,p);
printf("%s\n",out);
out[2]=0;
p=strtok(NULL,":");
}

[oolhyzcx]

对，用拼接函数可以实现

[oolhyzcx]

十分急，在线等……

[ljz888666555]

CString str(_T("00:FF:0A:0C:06:03"));
str.Replace(_T(":"),_T(",0x"));

[白云飘飘飘]

	char buff[]="00:FF:0A:0C:06:03";
	char *p=strtok(buff,":");
	while(p!=0)
	{

		int n;
		sscanf(p,"%x",&n);
		//保存n
		p=strtok(NULL,":");
	}

[oolhyzcx]

有错误
c.c:15: error: `n' undeclared (first use in this function)

[oolhyzcx]

最后能存在一个如m[]的数组中，m[]{0x00,0x01,0x02,0x03,0x04,0x05}这种格式