二维数组传递函数.

[saishow]

不知道怎么传数值进去.请大家帮忙看看什么地方出错了.

#include <stdio.h>
#include <stdlib.h>
#define NIAN 5
#define YUE 12
void xs (int suzi[][],int n,int x);

int main(int argc, char *argv[])
{
  int sss,ggg;
  int ss[NIAN][YUE]={{0,0,0,0,0,0,0,0,0,0,0,11},
                     {1,0,0,0,0,0,0,0,0,0,0,11},
                     {2,0,0,0,0,0,0,0,0,0,0,11},
                     {3,0,0,0,0,0,0,0,0,0,0,11},
                     {4,0,0,0,0,0,0,0,0,0,0,11},};
                     
  for (sss=0;sss<NIAN;sss++){
         for (ggg=0;ggg<YUE;ggg++){
         printf("%4d",ss[sss][ggg]);
         }
         printf("\n");
        }
  xs(ss,NIAN,YUE);
  system("PAUSE");	
  return 0;
}

void xs (int suzi[][],int n,int x){
     int i,k;
     for (i=0;i<n;i++){
         for (k=0;k<x;k++)
         printf("%4d",suzi[i],k);
         printf("\n");
        }
         printf("\n");
     return;
     }

[happytang]

修改，就是这么用

#include <stdio.h> 
#include <stdio.h>
#include <stdlib.h>
#define NIAN 5
#define YUE 12
void xs (int suzi[NIAN][YUE],int n,int x);

int main(int argc, char *argv[])
{
	int sss,ggg;
	int ss[NIAN][YUE]={{0,0,0,0,0,0,0,0,0,0,0,11},
	{1,0,0,0,0,0,0,0,0,0,0,11},
	{2,0,0,0,0,0,0,0,0,0,0,11},
	{3,0,0,0,0,0,0,0,0,0,0,11},
	{4,0,0,0,0,0,0,0,0,0,0,11},};

	for (sss=0;sss<NIAN;sss++){
		for (ggg=0;ggg<YUE;ggg++){
			printf("%4d",ss[sss][ggg]);
		}
		printf("\n");
	}
	xs(ss,NIAN,YUE);
	system("PAUSE");    
	return 0;
}

void xs (int suzi[NIAN][YUE],int n,int x){
	int i,k;
	for (i=0;i<n;i++){
		for (k=0;k<x;k++)
			printf("%4d",suzi[i][k]);//修改
		printf("\n");
	}
	printf("\n");
	return;
}

[yanghope]

你在函数声明时参数错啦，编译器只知道该数组的维数，但是并不知道传过来的数组的宽和高，void xs (int suzi[][YUE],int n,int x);或者是void xs (int suzi[NIAN][YUE],int n,int x);都是可以的。但是不能这样传过来void xs (int suzi[NIAN][],int n,int x);原因是数组在内存中存放时一行一行存放的，所以一定要知道数组的宽度，编译器会将会自动确定高度。

[saishow]

感谢二位...特别感谢2楼.