通过子函数给字符数组赋值无效，高分！！

[jiahehao]

我写了一个子函数，作用是把传进来参数input_char的每一个字节，按位取出来，存到另外一个参数 bit_array中去。

但是在我在主函数中读的时候，发现bit_array中全是空值。求助各位！！！

//convert char into bit
int ConvertToBit(char * bit_array, char * input_char, int * bit_count)
{
int i = 0;
int j = 0;
int s = 0;
unsigned char tmp_char, tmp_bit;

while( input_char[i] != '\0')
｛
//printf("the input_char is %d.\n", input_char[0]);
tmp_char = input_char[i];
for(j = 0; j < 8; j++)
{
tmp_bit = (tmp_char & (1 << 7));
tmp_bit = (tmp_char >> 7);
printf("the tmp_bit is %d.\n",tmp_bit);
//bit_array[s] = tmp_bit; 此方法赋完值后打印有值，去主函数打印则无值。
*bit_array++ = tmp_bit; //此方法赋完值后打印即无值。
tmp_char = tmp_char << 1;
s++;
}
i++;
}
*bit_count = s;
printf("bit_array is %s!, bit_count is %d.\n", bit_array, *bit_count);
}

main()
{
char new_comport_data[32];
char bit_data[256];
......
//convert byte to bit;
ConvertToBit(bit_data, new_comport_data, &bit_count);
printf("bit_data is %s!\n", bit_data);
......
}

[sduxiaoxiang]

 *bit_array++ = tmp_bit + ‘0’; //此方法赋完值后打印即无值。

[ryfdizuo]

#include <stdio.h>
#include <stdlib.h>

//convert char into bit
void ConvertToBit(char * bit_array, char * input_char, int * bit_count)
{
	int i = 0;
	int j = 0;
	int s = 0;
	unsigned char tmp_char, tmp_bit;

	while( input_char[i] != '\0')
	{
		//printf("the input_char is %d.\n", input_char[0]);
		tmp_char = input_char[i];
		for(j = 0; j < 8; j++)   
		{
			tmp_bit = (tmp_char & (1 << 7));
			tmp_bit = (tmp_char >> 7);
			printf("the tmp_bit is %d.\n",tmp_bit);
			
			*bit_array++ = tmp_bit + '0';		// 这里，将asc码数值转化为char, asc码0,1是不可打印的。。。
			tmp_char = tmp_char << 1;
			s++;
		}
		i++;
	}
	*bit_count = s;
	printf("bit_array is %s!, bit_count is %d.\n", bit_array, *bit_count);
}

void main()
{
	char new_comport_data[32] = {"abc"};
	char bit_data[256] = {0};			//初始化
	int bit_count = 0;

	//convert byte to bit;
	ConvertToBit(bit_data, new_comport_data, &bit_count);
	printf("bit_data is %s!\n", bit_data);
	
	system("PAUSE");
}
the tmp_bit is 0.
the tmp_bit is 1.
the tmp_bit is 1.
the tmp_bit is 0.
the tmp_bit is 0.
the tmp_bit is 0.
the tmp_bit is 0.
the tmp_bit is 1.
the tmp_bit is 0.
the tmp_bit is 1.
the tmp_bit is 1.
the tmp_bit is 0.
the tmp_bit is 0.
the tmp_bit is 0.
the tmp_bit is 1.
the tmp_bit is 0.
the tmp_bit is 0.
the tmp_bit is 1.
the tmp_bit is 1.
the tmp_bit is 0.
the tmp_bit is 0.
the tmp_bit is 0.
the tmp_bit is 1.
the tmp_bit is 1.
bit_array is !, bit_count is 24.
bit_data is 011000010110001001100011!
请按任意键继续. . .

[jixingzhong]

输出调试时，记得转化输出的字符为可见字符。
或者输出数值，而不是字符。

一般，直接单步调试，查看变量的值会比较直接。

[無_1024]

单步调试 会得到你想要的结果的 有时候时空格之类的

[就想叫yoko]

+1[Quote=引用 3 楼 jixingzhong 的回复:]
输出调试时，记得转化输出的字符为可见字符。
或者输出数值，而不是字符。

一般，直接单步调试，查看变量的值会比较直接。
[/Quote]

[jiahehao]

二楼的dizuo兄弟，你的代码在linux下为什么有的位，读出来是-48，-68，或者49之类的数字呢？而不是象你的，全部打出的是0，1？

[ryfdizuo]

[Quote=引用 6 楼 jiahehao 的回复:]

二楼的dizuo兄弟，你的代码在linux下为什么有的位，读出来是-48，-68，或者49之类的数字呢？而不是象你的，全部打出的是0，1？
[/Quote]
我的那段代码跟系统无关啊，
最终
你想要实现什么效果？
需要注意的是，最终二进制字符串011000010110001001100011是abc对应的acs码的二进制。
a的asc码97，b 98，c 99