请问这段代码的意义何在？什么意思？

[yangt1100]

         static TCHAR szMsg[1024]={0};
	unsigned char wch[CMD_LENGTH];
	DWORD dwBytesRead = 256;
	DWORD dwWritten;
	DWORD dwID = 0;
	char strMac[16];
	char szResult[25];
	m_bExitLoop = FALSE;
        while(m_bExitLoop == FALSE)
		{	
			memset(wch,0x00,sizeof(wch));
			memset(szBatteryCapacity,0x00,sizeof(szBatteryCapacity));
			Sleep(1000);
			ReadFile(hCom, wch, sizeof(wch), &dwBytesRead, NULL);
			int y = 0;
			DWORD dwWritten;
       if ((wch[y]=='0')&&(wch[y+1]=='1')&&(wch[y+2]=='1')&&(wch[y+3]=='6')&&(wch[y+4]=='0')&&(wch[y+5]=='1'))
		{
			GetDlgItem(IDC_DUT_MSG)->SetWindowTextW(L"Received OSVersion Writing command.");
			memcpy(m_chCurrentCmd,wch,16);
			m_iUtilityIndex = 0;
			DWORD i = (DWORD)wch[y+6] - 48;
			DWORD j = (DWORD)wch[y+7] - 48;
			serialLength = 10*i + j;
			memcpy(serialBuff, (wch + 8),serialLength);

其中，wch[]的值应该是01160116.这样子的话谁能帮我分析一下
DWORD i = (DWORD)wch[y+6] - 48;
DWORD j = (DWORD)wch[y+7] - 48;
serialLength = 10*i + j;
这一段代码的意义和具体值？？

[fontlose]

将wch的第6和第7个元素转换成10进制方式
DWORD i = (DWORD)wch[y+6] - '0';
DWORD j = (DWORD)wch[y+7] - '0';
serialLength = 10*i + j ;

[bluesea87]

serialLength值应该是16，三句话的作用是把“16”从ascll码转成整数16

[yangt1100]

然后呢？wch[y+6]=1，wch[y+7]=6，然后i=1，j=6？？？
memcpy(serialBuff, (wch + 8),serialLength);
是从第9位开始复制吗？

[fontlose]

01160116xxxxxxxxxxxxxxxxxxxxxx
将xxxxxxxxxxxxxxx（16个）考到serialBuff内

[迷世书童]

关注一下

[bluesea87]

[Quote=引用 4 楼 fontlose 的回复:]
01160116xxxxxxxxxxxxxxxxxxxxxx
将xxxxxxxxxxxxxxx（16个）考到serialBuff内
[/Quote]
+1

[bluesea87]

[Quote=引用 3 楼 yangt1100 的回复:]
然后呢？wch[y+6]=1，wch[y+7]=6，然后i=1，j=6？？？
memcpy(serialBuff, (wch + 8),serialLength);
是从第9位开始复制吗？
[/Quote]
应该是wch[y+6]='1'，wch[y+7]='6'

[yangt1100]

好 谢谢大家 我搞明白了 大家太热心了！