IPV6地址转换问题?

2011-06-13 06:12:05 1k 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

IP子网划分，DNS和IPv6基础知识点总结 1.IP子网划分的类型、方法以及分类IP地址的低效性，2.子网掩码的计算方法，以及VLSM和CLDR的基本内容，3.DNS的作用、模式结构和问题，4.IPv6的优缺点和表示方式。阅读详情

现在有一个IPV6的IP地址：string ip6 = "fe80::2e0:4cff:fe20:55db";

怎么把这个地址转换到一个in6_addr 变量里面？

string ip6 = "fe80::2e0:4cff:fe20:55db";

in6_addr adr6 = ?

...全文

如何让PJSIP 支持IPV6 PJSIP 是非常精致的SIP Client 协议栈, 其层次结构清晰的API设计, 良好的跨平台属性, 在业内有很高的声誉, 有不少SIP商业应用基于它开发. 可是PJSIP早期版本从未对IPV6有很好的支持. Apple 在今年5月时发布声明, 要求6月1号以后所有的iOS应用都必须包含对IPV6-ONLY网络的支持. 这个对基于PJSIP开发的iOS应用来说可谓是当头阅读详情

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西湖秀才 2011-06-17

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随便手写一个，XP+VS2008下测试通过，楼主试试！







#include "stdafx.h"

#include <Ws2tcpip.h >



static union

{

	char c[4];

	unsigned long l;

}endian_test ={'l','?','?','b'};



#define   ENDIAN_NESS ((char)endian_test.l)





int Count(char * pointer,bool bNoDoubleColon,unsigned short * Word)

{

	int i;



	for( i=0;i<8;i++)

	{

		while(*pointer!=':'&&*pointer!='\0')

		{				

			pointer++;

			Word[i]++;

		}

		pointer++;



		if(!bNoDoubleColon&&*pointer=='\0')

		{

			break;

		}

	}



	return (i==8)?i:i+1;		



}





void CopyData(char * pointer,int num,unsigned short * Word)

{

	int nValue=0;

	char buf[5];

	for (int i=0;i<num;i++)

	{

		nValue=0;

		memset(buf,0,sizeof(buf));

		strncpy(buf,pointer,Word[i]);

		pointer+=(Word[i]+1);

		sscanf_s(buf,"%x",&nValue); 

		Word[i]=nValue;



	}



}





void Inet6_Addr(char * Ipv6Str,PIN6_ADDR pAddr)

{



	char * pointer;



	unsigned short Word[8]={0};

	int nNum;

	char buf[5]={0};	

	char * Pos=strstr(Ipv6Str,"::");



	if (Pos==NULL)            //No ::

	{

		int n=Count(Ipv6Str,TRUE,Word);

		pointer=Ipv6Str;

		CopyData(pointer,n,Word);			



	}

	else

	{

		if (strlen(Ipv6Str)==2)  // Only ::

		{			

			return;

		}



		int nPos=Pos-Ipv6Str;



		if (nPos==0)          //:: start

		{	

			pointer=Ipv6Str+2;

			nNum=Count(pointer,FALSE,Word);



			CopyData(pointer,nNum,Word);



			MoveMemory(&Word[8-nNum],&Word[0],(nNum)*sizeof(unsigned short));

			ZeroMemory(&Word[0],(8-nNum)*sizeof(unsigned short));			





		}

		else if (nPos==strlen(Ipv6Str)-2)  //:: end

		{			

			char  cTemp[16]={0};

			strncpy(cTemp,Ipv6Str,nPos);	



			pointer=cTemp;

			nNum=Count(pointer,FALSE,Word);



			CopyData(pointer,nNum,Word);	





		}

		else                         //:: middle

		{

			unsigned short Temp[8]={0};

			char cTemp1[16]={0};

			char cTemp2[16]={0};

			strncpy(cTemp1,Ipv6Str,nPos);

			strncpy(cTemp2,Ipv6Str+nPos+2,strlen(Ipv6Str)-nPos-2);

			pointer=cTemp1;

			nNum=Count(pointer,FALSE,Word);

			CopyData(pointer,nNum,Word);

			pointer=cTemp2;



			nNum=Count(pointer,FALSE,Temp);

			CopyData(pointer,nNum,Temp);			

			MoveMemory(&Word[8-nNum],&Temp[0],(nNum)*sizeof(unsigned short));		



		}	



	}



	

	if (ENDIAN_NESS=='l')               //little endian

	{

		for(int i=0;i<8;i++)  

		{

			if(Word[i]!=0)

			{

				unsigned short temp;

				temp=Word[i]>>8&0x00FF;

				Word[i]= Word[i]<<8;

				Word[i]|=temp;

			}		

		}

	}



	

	memcpy(pAddr->u.Word,Word,sizeof(Word));



}





int _tmain(int argc, _TCHAR* argv[])

{ 



	IN6_ADDR in6Addr;

	ZeroMemory(&in6Addr,sizeof(in6Addr));



	/*printf("IP Address:%s\n","1A2:24:3:4D:5:6C:7:8FE");

	Inet6_Addr("1A2:24:3:4D:5:6C:7:8FE",&in6Addr);



	printf("IP Address:%s\n","::6C:7:8FE");

	Inet6_Addr("::6C:7:8FE",&in6Addr);



	printf("IP Address:%s\n","6C:7:8FE::");

	Inet6_Addr("6C:7:8FE::",&in6Addr);*/



	printf("IP Address:%s\n","6C:7:8FE::123:5E");

	Inet6_Addr("6C:7:8FE::123:5E",&in6Addr);



	printf("After Translate:\n");

	for (int i=0;i<8;i++)

	{

		printf(" Word[%d]:0x%04x",i,in6Addr.u.Word[i]);

	}	

	

	return 0;

}

sharptiger123 2011-06-16

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用ipV6 必须先安装系统自带的 ipv6 协议

西湖秀才 2011-06-16

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是在不行自己定义个，不麻烦吧

giant1st 2011-06-16

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参考：http://blog.csdn.net/sunboy_2050/archive/2010/12/27/6100734.aspx
IPv4：

IP字符串 ——》网络字节流

inet_addr、inet_network、inet_aton

程序代码：



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    #include <stdio.h>  

    #include <stdlib.h>  

    #include <unistd.h>  

    #include <string.h>  

    #include <netinet/in.h>  

    #include <sys/socket.h>  

    #include <sys/types.h>  

      

    int main()  

    {  

        char ip[] = "192.168.0.74";  

        long r1, r2, r3;  //long  

        struct in_addr addr;  

      

        r1 = inet_addr(ip); //返回网络字节序  

        if(-1 == r1){  

            printf("inet_addr return -1\n");  

        }else{  

            printf("inet_addr ip: %ld\n", r1);  

        }  

          

        r2 = inet_network(ip);    //返回主机字节序  

        if(-1 == r2){  

            printf("inet_addr return -1\n");  

        }else{  

            printf("inet_network ip: %ld\n", r2);   

            printf("inet_network ip: %ld\n", ntohl(r2));   //ntohl: 主机字节序 ——> 网络字节序  

        }  

          

        r3 = inet_aton(ip, &addr);  //返回网络字节序  

        if(0 == r3){  

            printf("inet_aton return -1\n");  

        }else{  

            printf("inet_aton ip: %ld\n", addr.s_addr);  

        }  

      

    /*****  批量注释的一种方法  *****/  

    #if 0    

        r3 = inet_aton(ip, addr);  

        if(0 == r3){  

            printf("inet_aton return -1\n");  

        }else{  

            printf("inet_aton ip: %ld\n", ntohl(addr.s_addr));  

        }  

    #endif  

      

        return 0;  

    }  



运行结果：



[work@db-testing-com06-vm3.db01.baidu.com net]$ gcc -W -o inet_addr inet_addr.c

[work@db-testing-com06-vm3.db01.baidu.com net]$ ./inet_addr                    

inet_addr ip: 1241557184

inet_network ip: -1062731702

inet_network ip: 1241557184

inet_aton ip: 1241557184 



--------------------------------------------------------------------------



IP字符串 《——》 网络字节流



inet_addr、inet_aton、inet_ntoa



 程序代码：



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    #include <stdio.h>  

    #include <sys/socket.h>  

    #include <netinet/in.h>  

    #include <arpa/inet.h>  

    #include <string.h>  

    int main(int argc, char *argv[])  

    {  

        char ip1[] = "192.168.0.74";  

        char ip2[] = "211.100.21.179";  

        struct in_addr addr1, addr2;  

        long l1, l2;  

        l1 = inet_addr(ip1);   //IP字符串——》网络字节  

        l2 = inet_addr(ip2);  

        printf("IP1: %s\nIP2: %s\n", ip1, ip2);  

        printf("Addr1: %ld\nAddr2: %ld\n", l1, l2);  

          

        memcpy(&addr1, &l1, 4); //复制4个字节大小  

        memcpy(&addr2, &l2, 4);  

        printf("%s <--> %s\n", inet_ntoa(addr1), inet_ntoa(addr2)); //注意：printf函数自右向左求值、覆盖  

        printf("%s\n", inet_ntoa(addr1)); //网络字节 ——》IP字符串  

        printf("%s\n", inet_ntoa(addr2));  

        return 0;  

    }  



运行结果：



[work@db-testing-com06-vm3.db01.baidu.com net]$ gcc -W -o inet_ntoa inet_ntoa.c 



[work@db-testing-com06-vm3.db01.baidu.com net]$ ./inet_ntoa                                      



IP1: 192.168.0.74



IP2: 211.100.21.179



Addr1: 1241557184



Addr2: 3004523731



192.168.0.74 <--> 192.168.0.74



192.168.0.74



211.100.21.179



============================================================= 



IPv6：



IPv4 字符串 《——》网络字节流



inet_pton、inet_ntop



程序代码：



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    #include <stdio.h>  

    #include <sys/types.h>  

    #include <sys/socket.h>  

    #include <arpa/inet.h>  

      

    int main()  

    {  

        char ip[] = "192.168.0.74";   

        struct in_addr addr;  

          

        int ret = inet_pton(AF_INET, ip, (void *)&addr);   //IP字符串 ——》网络字节流  

        if(0 == ret){  

            printf("inet_pton error, return 0\n");  

            return -1;  

        }else{  

            printf("inet_pton ip: %ld\n", addr.s_addr);  

            printf("inet_pton ip: 0x%x\n", addr.s_addr);  

        }  

      

        const char *pstr = inet_ntop(AF_INET, (void *)&addr, ip, 128);  //网络字节流 ——》IP字符串  

        if(NULL == pstr){  

            printf("inet_ntop error, return NULL\n");  

            return -1;  

        }else{  

            printf("inet_ntop ip: %s\n", ip);  

        }  

          

        return 0;  

    }  



运行结果：



[work@db-testing-com06-vm3.db01.baidu.com net]$ gcc -W -o inet_ptoa inet_ptoa.c

[work@db-testing-com06-vm3.db01.baidu.com net]$ ./inet_ptoa                    

inet_pton ip: 1241557184

inet_pton ip: 0x4a00a8c0

inet_ntop ip: 192.168.0.74



--------------------------------------------------------------------------



IPv6 字符串 《——》网络字节流



inet_pton、inet_ntop



程序代码：



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    #include <stdio.h>  

    #include <stdlib.h>  

    #include <string.h>  

    #include <arpa/inet.h>  

      

    int   

    main(int argc, char **argv)  

    {  

        unsigned char buf[sizeof(struct in6_addr)];  

        int domain, s;  

        char str[INET6_ADDRSTRLEN];  

      

        if(argc != 3){  

            fprintf(stderr, "usage: %s {i4|i6|<num>} string\n", argv[0]);  

            exit(EXIT_FAILURE);  

        }  

      

        domain = (strcmp(argv[1], "i4") == 0) ? AF_INET:(strcmp(argv[1], "i6") == 0) ? AF_INET6 : atoi(argv[1]);  

          

        //IP字符串 ——》网络字节流  

        s = inet_pton(domain, argv[2], buf);  

        if(s<=0){  

            if(0 == s)  

                fprintf(stderr, "Not in presentation format\n");  

            else  

                perror("inet_pton");  

            exit(EXIT_FAILURE);  

        }  

      

        //网络字节流 ——》IP字符串  

        if(inet_ntop(domain, buf, str, INET6_ADDRSTRLEN) == NULL){    

            perror("inet ntop\n");  

            exit(EXIT_FAILURE);  

        }  

      

        printf("%s\n", str);  

        exit(EXIT_SUCCESS);  

    }  



运行结果：



[work@db-testing-com06-vm3.db01.baidu.com net]$ gcc -W -o inet_ptoa6 inet_ptoa6.c                              

[work@db-testing-com06-vm3.db01.baidu.com net]$ ./inet_ptoa6 i6 0:0:0:0:0:FFFF:204.152.189.116  

::ffff:204.152.189.116

[work@db-testing-com06-vm3.db01.baidu.com net]$ ./inet_ptoa6 i4 204.152.189.116              

204.152.189.116

mukefei77 2011-06-13

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LONG NTAPI RtlIpv6StringToAddress(

  __in   PCTSTR S,

  __out  PCTSTR *Terminator,

  __out  IN6_ADDR *Addr

);



LPTSTR NTAPI RtlIpv6AddressToString(

  __in   const IN6_ADDR *Addr,

  __out  LPTSTR S

);

rroamer 2011-06-13

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另外注明一下，需要能在XP和WINDWOS 7下都可以用的，

IPV6地址转换问题?

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