double减法。。小数部分

[「已注销」]

#include<stdio.h>
char str1[][3]={"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"};
char str2[][3]={"亿","仟","佰","拾","万","仟","佰","拾","元","角","分"};
void main()
{
	double r,y;
	char str3[20];
	int i,n,j,m,x,k,pd=0;
	printf("请输入金额：");
	scanf("%lf",&r);
    y=r-(r/1);        
    x=r/1;            
	for(i=0;i<=11;i++)  
	{
	  m=x%10;
      str3[11-i]=m;
      x=x/10;
	}
    str3[12]=(int)(y*10);   
    str3[13]=(int)(y*100)%10;
    for(k=0;k<=13 && pd==0;k++)      
	{
		if(str3[k]>0)
	  {
			pd=1;n=k;
	  }
	}
	for(j=n;j<=13;j++)
		printf("%s%s",str1[str3[j]],str2[j-3]);
    putchar(10);
}

小数部分有问题，还有DOUBLE 近似的问题。谢谢了。

[「已注销」]

帮帮忙了 谢谢了。

[sduxiaoxiang]

y=r-((int)r/1);  

y是小数部分

[philip_puma]

好好学习，天天向上、

[「已注销」]

呵呵 刷分啊

[WayneXuan]

y=r-(r/1);改成y=r-(int)r;

[lengwuqin]

帮你写好了，改了你的程序，分之后的就输不出来了，这个没帮你写，代码如下：

#include<stdio.h>
char str1[][3]={"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"};
char str2[][3]={"亿","仟","佰","拾","万","仟","佰","拾","元","角","分"};
void main()
{
double r,y;
char str3[20];
int i,n,j,m,x,k,pd=0;
printf("请输入金额：");
scanf("%lf",&r);
y=r-(int)(r/1);
x=r/1;
for(i=0;i<=11;i++)
{
m=x%10;
str3[11-i]=m;
x=x/10;
}

j=(int)(y*10);
i=0;
while( j!=0 )
{
str3[12+i]=j;
y=y*10-j;
j=(int)(y*10);
i++;
printf("j=%d\n",j);
}
for(k=0;k<=13 && pd==0;k++)
{
if(str3[k]>0)
{
pd=1;n=k;
}
}
for(j=n;j<=13;j++)
printf("%s%s",str1[str3[j]],str2[j-3]);
putchar(10);
}

[coldicy2007]

[Quote=引用 8 楼 sduxiaoxiang 的回复:]
C/C++ code

y=r-((int)r/1);


y是小数部分
[/Quote]
求教，为什么要除以1？

[sduxiaoxiang]

-[Quote=引用 17 楼 coldicy2007 的回复:]
引用 8 楼 sduxiaoxiang 的回复:
C/C++ code

y=r-((int)r/1);


y是小数部分

求教，为什么要除以1？
[/Quote]
源代码上改的
除不除无所谓

[JiangXiang]

y=r-(int)r;