求指点！

[muku9527]

#include"stdio.h"

int main()
{
__int16 a=324;
__int16 b=68;
char f='A';
printf("a=%c\n",a);
printf("b=%c\n",b);
printf("sizeof(f)=%d\n",sizeof (f));
printf("sizeof('A')=%d\n",sizeof ('A'));
return 0;
}//这个地方sizeof (f)=1；sizeof ('A')=4为什么？

[cunyan_0519]

char f='A';说明f是字符型的，肯定长度为1个字节的。而'A'按整型输出的。

[pengzhixi]

An integer character constant has type int. The value of an integer character constant containing a single character that maps to a single-byte execution character is the numerical value of the representation of the mapped character interpreted as an integer. The value of an integer character constant containing more than one character (e.g.,'ab'), or containing a character or escape sequence that does not map to a single-byte execution character, is implementation-defined.


C标准对字符字面量的规定是 has type int.

[pengzhixi]

如果是C++也许结果就是1而不是4了。

[CJacky++]

Mark.

[zsc_ericluo]

你那里是%d输出，可能你那个编译器默认int是4字节，所以结果是4咯！

[muku9527]

[Quote=引用 2 楼 pengzhixi 的回复:]
An integer character constant has type int. The value of an integer character constant containing a single character that maps to a single-byte execution character is the numerical value of the repres……
[/Quote]

果断给力，谢谢！

[yjq1987]

vs2010编译运行两个输出的都是1啊。