还能更精简的么？ 把20个随机数存入一个数组，然后输出数组中的最小值和下标。

[WYD2608]

用一位数组编程：把20个随机数存入一个数组，然后输出数组中的最小值和下标。

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
main()
{
	int i,Minarr,Mark,arr[20];
	srand((unsigned)time(NULL));
	for (i=0;i<20;i++)
	{
		arr[i]= rand()%100;
		if (i==0)
			Minarr = arr[i];
		else if (arr[i]<Minarr)
		{
			Minarr = arr[i];
			Mark = i;
		}
		if (i==19)
			printf("The Minarr is arr[%d]=%d\n",Mark,Minarr);
	}
}

[無_1024]

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main()
{
    int i,Minarr,Mark = 0,arr[20];
    srand((unsigned)time(NULL));//可以省掉一些不必要的比较判断时间
	arr[0] =  rand()%100;
	Minarr = arr[0];
    for ( i = 1;i < 20; ++i )
    {
        arr[i]= rand()%100;
		if ( arr[i] < Minarr)
        {
            Minarr = arr[i];
            Mark = i;
        }           
    }
	printf("The Minarr is arr[%d]=%d\n",Mark,Minarr);
	return 0;
}

[xiejijun_05]

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

void main()
{
    int Minarr = 100; 
	int Mark = 0;
	int arr[20] = {0};

    srand((unsigned)time(NULL));

    for (int i = 0; i < 20; i++)
    {
        arr[i]= rand()%100;

        if (arr[i] <Minarr)
        {
            Minarr = arr[i];
            Mark = i;
        }
    }
	printf("The Minarr is arr[%d] = %d\n", Mark,Minarr);
}

[编程点滴]

#include <stdio.h>
#include <stdlib.h>
#include <time.h>
main()
{
    int i,Minarr,Mark,arr[20];
    srand((unsigned)time(NULL));
	Minarr = arr[0] = rand()%100;
	Mark = 0;
    for (i=1;i<20;i++)
    {
        arr[i]= rand()%100;
        if (arr[i]<Minarr)
        {
            Minarr = arr[i];
            Mark = i;
        }
    }
    printf("The Minarr is arr[%d]=%d\n",Mark,Minarr);
}