如何将一字符串动态赋值成16进制值，内含详细代码（总共几行）

[chenchen_2011]

MDK环境下，有如下实现

uint8_t Settimebuf[7];

Settimebuf[6] = 0x12; //年
Settimebuf[5] = 0x07; //周
Settimebuf[4] = 0x06; //月
Settimebuf[3] = 0x17; //日
Settimebuf[2] = 0x10; //时
Settimebuf[1] = 0x23; //分
Settimebuf[0] = 0x20;//秒

Set1381Time(Settimebuf);

现有一个char变量动态记录了年月日时分秒的信息"120617102320"，请教如何将字符串中相应时间信息赋值成如上，以实现可动态设置时间信息

谢谢，一个非C程序员

[turing-complete]

不知道你为什么要用16进制，如果一定要用的话，那你就改一处代码即可，把×10 改成×16

#include <stdio.h>

#define GET_NUM(ch) ((ch) - '0')

unsigned char* set_buf(const char* str, unsigned char* buf, const size_t LEN) {
    size_t i;
    unsigned char num = 0;
    for (i = 0; i < LEN; ++i) {
        num = GET_NUM(str[2*i]) * 10 + GET_NUM(str[2*i+1]);
        buf[i] = num;
    }

    return buf;
}

/* 测试代码 */
int main() {
    const char *str = "120617102320";
    size_t i;
    unsigned char buf[7];
    const size_t LEN = sizeof(buf);
    set_buf(str, buf, 7);
    for (i = 0; i < LEN; ++i) {
        printf("%d\n", buf[i]);
    }
    return 0;
}

[jiuchang]

基本上如1楼所说，就是每两个字节转换为一个16进制数，高位乘以10或16再加上低位就可以了，10进制或16进制都很容易的

[qq120848369]

[User:root Time:21:23:37 Path:/home/liangdong/c]$ make
gcc -g -I./include   -c -o src/main.o src/main.c
gcc -o output src/main.o -lpthread -lm -lz
Makefile done.
[User:root Time:21:23:37 Path:/home/liangdong/c]$ ./output 
0x12 0x7 0x6 0x17 0x10 0x23 0x20 
[User:root Time:21:23:38 Path:/home/liangdong/c]$ cat src/main.c 
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <stdint.h>

int strpuint8(const char *time, uint8_t *buf) {
        if (!time) {
                return -1;
        }
        int i;
        for (i = 0; i != 7; ++ i) {
                if (sscanf(time + i * 2, "%2x", buf + i) != 1) {
                        return -1;
                }
        }
        return 0;
}

int main(int argc, char* const argv[]) {
        uint8_t set_time_buf[7];
        const char *time = "12070617102320";
        int ret = strpuint8(time, set_time_buf);
        if (ret == 0) {
                int i;
                for (i = 0; i != 7; ++ i) {
                        printf("0x%x ", set_time_buf[i]);
                }
        }
        printf("\n");
        return 0;
}