编写程序颠倒句子中单词的顺序

[qhmilanista]

Enter a sentece: you can cage a swallow can't you? （下划线为用户输入的字符）
Reversal of sentence: you can't swallow a cage can you?

提示：用循环逐个读取字符，然后将他们储存在一个一维字符数组中。当遇到句话、问号或者感叹号（成为“终止字符”）时，终止循环并把终止字符存储在一个char类型的变量中。然后再用一个循环反向搜索数组，找到最后一个单词的起始位置。显示最后一个单词，然后反向搜索倒数第二个单词。重复这一过程，直至到达数组的起始位置。最后显示出终止字符。

[ies_sweet]

算法基本上也给出来了
思路都有了
楼主可以自己动手编码的

[Corner]

void reserverSentence(const char* sentence, int len, char sep)
{
    int *index_mark = new int[len]();
    int word_num = 1;
    index_mark[0] = -1;
    for(int i = 0; i < len; i++)
    {
        if(sentence[i] == ' ')
        {
            index_mark[word_num] = i;
            word_num++;
        }
    }

    char * word;
    int word_start, word_len;
    index_mark[word_num] = len;
    word_num++;
    for(int i = word_num - 1; i > 0; i--)
    {
        word_start = index_mark[i - 1] + 1;
        word_len = index_mark[i] - word_start;
        word = new char[word_len + 1]();
        memcpy(word, sentence + word_start, word_len);
        cout<<word;
        if(i != 1)
        {
            cout<<" ";
        }
        delete[] word;
    }
    cout<<sep<<endl;
    delete[] index_mark;
}

void reserverSentences(const char* sentences, int len)
{
    int old_pos = -1;
    for(int i = 0; i < len; i++)
    {
        if(sentences[i] == '.' || sentences[i] == '?' || sentences[i] == '!')
        {
            reserverSentence(sentences + old_pos + 1, i - old_pos - 1, sentences[i]);
            old_pos = i;
        }        
    }
}

int _tmain(int argc, _TCHAR* argv[])
{    
    cout<<"Enter a sentence"<<endl;
    string line;
    getline(cin, line);
    reserverSentences(line.c_str(), line.size());
    system("pause");
    return 0; 
}

执行结果：
Enter a sentence
How are you? I am fine.What Can I do for you?No thanks.
you are How?
fine am I .
you for do I Can What?
thanks No.
请按任意键继续. . .

[qhmilanista]

[Quote=引用 2 楼 的回复:]
C/C++ code


void reserverSentence(const char* sentence, int len, char sep)
{
int *index_mark = new int[len]();
int word_num = 1;
index_mark[0] = -1;
for(int i = 0; i < len; i+……
[/Quote]

楼上能否写成C语言的？

[nice_cxf]

明显作业。。。。

[Corner]

[Quote=引用 3 楼 的回复:]
引用 2 楼 的回复:
C/C++ code


void reserverSentence(const char* sentence, int len, char sep)
{
int *index_mark = new int[len]();
int word_num = 1;
index_mark[0] = -1;
for(int i = 0; i < len; i+……
……
[/Quote]
代码就是C语言的，测试用的C++，你自己可以用C语言去测试

[Defonds]

自己动手吧

[把握]

程序比较简单了，你的思想对了

[zhanghuan007]

#include<stdio.h> #include<string.h> int main(void){ char symbol; char array[100]; int len,index,i,j; printf("enter your sentence:"); gets(array); printf("the sentence you enter is:"); puts(array); printf("\n"); len=strlen(array); index=len-1; for(i=len-1;i>=0;i--){//最完美的代码 if(array[i]==' '){ for(j=i+1;j<index;j++){ printf("%c",array[j]); } printf(" "); index=i; }else if(i==0){ for(j=i;j<index;j++){ printf("%c",array[j]); } } } /* for(i=len-1;i>=0;i--){//反打的第一个单词有空格 if(array[i]==' '||i==0){ for(j=i;j<index;j++){ printf("%c",array[j]); } printf(" "); index=i; } }*/ /* for(i=len-1;i>=0;i--){//第一个单词打不出来 if(array[i]==' '||i==0){ for(j=i+1;j<index;j++){ printf("%c",array[j]); } printf(" "); index=i; } }*/ printf("%c",array[len-1]); printf("\n"); return 0; }

[baidu_26952089]

#include <stdio.h> int main(void) { char a[200],ch; int i,j,x,b; printf("Enter a sentence:"); for(i=0;i<200;i++){ scanf("%c",&a[i]); if(a[i]=='\n'){ x=i; break; } } ch=a[x-1]; b=x-1; printf("Reversal of sentence:"); for(i=(x-1);i>=0;i--){ if(a[i]==' '){ for(j=i+1;j<b;j++){ printf("%c",a[j]); } printf(" "); b=i; } else if(i==0){ for(j=0;j<b;j++){ printf("%c",a[j]); } } } printf("%c",ch); return 0; }