一个小问题 不懂

[jdwq33]

#include <stdio.h>

int main()
{
double x, y, z;

x = 1;
z = 3/2;
y = x + z;

printf("%f\n", z);
printf("%f\n", y);

return 0;
}

//在这里的Z为什么等于1，而不是1.5呢？？？大师能帮忙解决一下吗？？摆脱了

[Corner]

因为3和2都是int型的，计算结果也是int型，然后转换成double赋值给z，所以结果是1。如下修改后就是1.5了

    double x, y, z;

    x = 1;
    z = (double)3/2;
    y = x + z;

    printf("%f\n", z);
    printf("%f\n", y);

[jdwq33]

对的 谢谢大师帮忙解惑啊 呵呵

[赵4老师]

x = 1.0;
z = 3.0/2.0;
常量也有类型：
C++ Floating-Point Constants
Floating-point constants specify values that must have a fractional part. These values contain decimal points (.) and can contain exponents.

Syntax

floating-constant :

fractional-constant exponent-partopt floating-suffixopt
digit-sequence exponent-part floating-suffixopt

fractional-constant :

digit-sequenceopt . digit-sequence
digit-sequence .

exponent-part :

e signopt digit-sequence
E signopt digit-sequence

sign : one of

+ –

digit-sequence :

digit
digit-sequence digit

floating-suffix :one of

f l F L

Floating-point constants have a “mantissa,” which specifies the value of the number, an “exponent,” which specifies the magnitude of the number, and an optional suffix that specifies the constant’s type. The mantissa is specified as a sequence of digits followed by a period, followed by an optional sequence of digits representing the fractional part of the number. For example:

18.46
38.

The exponent, if present, specifies the magnitude of the number as a power of 10, as shown in the following example:

18.46e0 // 18.46
18.46e1 // 184.6

If an exponent is present, the trailing decimal point is unnecessary in whole numbers such as 18E0.

Floating-point constants default to type double. By using the suffixes f or l (or F or L — the suffix is not case sensitive), the constant can be specified as float or long double, respectively.

Although long double and double have the same representation, they are not the same type. For example, you can have overloaded functions like

void func( double );

and

void func( long double );

[xiaoguailong3]

你可以用:z = 3.0/2.0

[xiaoguailong3]

你可以用:z = 3.0/2.0

[manxiSafe]

在C语言中3/2=1，不会等于1.5的
你要 这样 c=3.0/2 就会转换成浮点型的结果

[yehailin11]

这个的确是很小得问题

[jdwq33]

C真是博大精深啊