c 如何计算每个一小时

banmiton 2012-10-16 05:07:22
如题,我想判断每个一小时触发某事件,该如何计算每隔一小时?用秒算好还是小时相减好?
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AndyZhang 2012-10-17
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GetTickCount()
赵4老师 2012-10-16
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仅供参考
#pragma comment(lib,"user32")
#include <stdio.h>
#include <time.h>
#include <sys/timeb.h>
#include <windows.h>
char datestr[16];
char timestr[16];
char mss[4];
void log(char *s) {
struct tm *now;
struct timeb tb;

ftime(&tb);
now=localtime(&tb.time);
sprintf(datestr,"%04d-%02d-%02d",now->tm_year+1900,now->tm_mon+1,now->tm_mday);
sprintf(timestr,"%02d:%02d:%02d",now->tm_hour ,now->tm_min ,now->tm_sec );
sprintf(mss,"%03d",tb.millitm);
printf("%s %s.%s %s",datestr,timestr,mss,s);
}
VOID CALLBACK myTimerProc1(
HWND hwnd, // handle of window for timer messages
UINT uMsg, // WM_TIMER message
UINT idEvent, // timer identifier
DWORD dwTime // current system time
) {
log("In myTimerProc1\n");
}
VOID CALLBACK myTimerProc2(
HWND hwnd, // handle of window for timer messages
UINT uMsg, // WM_TIMER message
UINT idEvent, // timer identifier
DWORD dwTime // current system time
) {
log("In myTimerProc2\n");
}
int main() {
int i;
MSG msg;

SetTimer(NULL,0,1000,myTimerProc1);
SetTimer(NULL,0,2000,myTimerProc2);
for (i=0;i<20;i++) {
Sleep(500);
log("In main\n");
if (GetMessage(&msg,NULL,0,0)) {
TranslateMessage(&msg);
DispatchMessage(&msg);
}

}
return 0;
}
//2012-07-26 17:29:06.375 In main
//2012-07-26 17:29:06.875 In myTimerProc1
//2012-07-26 17:29:07.375 In main
//2012-07-26 17:29:07.875 In myTimerProc2
//2012-07-26 17:29:08.375 In main
//2012-07-26 17:29:08.375 In myTimerProc1
//2012-07-26 17:29:08.875 In main
//2012-07-26 17:29:08.875 In myTimerProc1
//2012-07-26 17:29:09.375 In main
//2012-07-26 17:29:09.890 In myTimerProc2
//2012-07-26 17:29:10.390 In main
//2012-07-26 17:29:10.390 In myTimerProc1
//2012-07-26 17:29:10.890 In main
//2012-07-26 17:29:10.890 In myTimerProc1
//2012-07-26 17:29:11.390 In main
//2012-07-26 17:29:11.890 In myTimerProc2
//2012-07-26 17:29:12.390 In main
//2012-07-26 17:29:12.390 In myTimerProc1
//2012-07-26 17:29:12.890 In main
//2012-07-26 17:29:12.890 In myTimerProc1
//2012-07-26 17:29:13.390 In main
//2012-07-26 17:29:13.890 In myTimerProc2
//2012-07-26 17:29:14.390 In main
//2012-07-26 17:29:14.390 In myTimerProc1
//2012-07-26 17:29:14.890 In main
//2012-07-26 17:29:14.890 In myTimerProc1
//2012-07-26 17:29:15.390 In main
//2012-07-26 17:29:15.890 In myTimerProc2
//2012-07-26 17:29:16.390 In main
//2012-07-26 17:29:16.390 In myTimerProc1
//2012-07-26 17:29:16.890 In main
//2012-07-26 17:29:16.890 In myTimerProc1
//2012-07-26 17:29:17.390 In main
//2012-07-26 17:29:17.890 In myTimerProc2
//2012-07-26 17:29:18.390 In main
//2012-07-26 17:29:18.390 In myTimerProc1
//2012-07-26 17:29:18.890 In main
//2012-07-26 17:29:18.890 In myTimerProc1
//2012-07-26 17:29:19.390 In main
//2012-07-26 17:29:19.890 In myTimerProc2
xiaoxiao8310 2012-10-16
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适合用timer实现.不需要自己去计算时间.
huangwenshen 2012-10-16
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用秒计算。用time(null)记录两次的时间,然后计算差值。

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