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c 如何计算每个一小时

2012-10-16 05:07:22 302 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

banmiton 墨衍会员 · AI 创作全网分发关注 + 加入社区

c语言解决时间计算相加减的问题本来直接用小时减去小时，分钟减去分钟即可，但是经过调试发现，如果是3时40分减去4时50分的情况，小时位会输出负数，所以每次计算前将其化为分钟进行加减，输出换成小时即可。程序源码 #include <stdio.h> int main() { int hour1, minute1; int hour2, minute2; scanf("%d %d", &hour1, &minute1); scanf("%d %d", &hour2, &amp 阅读详情

如题，我想判断每个一小时触发某事件，该如何计算每隔一小时？用秒算好还是小时相减好？

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Synopsys AXI VIP 从环境搭建到首个验证场景运行本文详细介绍了Synopsys AXI VIP从环境搭建到首个验证场景运行的全过程，包括VIP安装、示例工程生成、验证环境解析、仿真调试技巧及进阶优化。特别针对AXI协议验证中的常见问题提供了实用解决方案，帮助工程师快速掌握这一SoC验证必备工具。阅读详情

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切换为时间正序

AndyZhang 2012-10-17

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GetTickCount()

赵4老师 2012-10-16

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仅供参考

#pragma comment(lib,"user32")

#include <stdio.h>

#include <time.h>

#include <sys/timeb.h>

#include <windows.h>

char datestr[16];

char timestr[16];

char mss[4];

void log(char *s) {

    struct tm *now;

    struct timeb tb;



    ftime(&tb);

    now=localtime(&tb.time);

    sprintf(datestr,"%04d-%02d-%02d",now->tm_year+1900,now->tm_mon+1,now->tm_mday);

    sprintf(timestr,"%02d:%02d:%02d",now->tm_hour     ,now->tm_min  ,now->tm_sec );

    sprintf(mss,"%03d",tb.millitm);

    printf("%s %s.%s %s",datestr,timestr,mss,s);

}

VOID CALLBACK myTimerProc1(

  HWND hwnd, // handle of window for timer messages

  UINT uMsg, // WM_TIMER message

  UINT idEvent, // timer identifier

  DWORD dwTime // current system time

) {

 log("In myTimerProc1\n");

}

VOID CALLBACK myTimerProc2(

  HWND hwnd, // handle of window for timer messages

  UINT uMsg, // WM_TIMER message

  UINT idEvent, // timer identifier

  DWORD dwTime // current system time

) {

 log("In myTimerProc2\n");

}

int main() {

    int i;

    MSG msg;



    SetTimer(NULL,0,1000,myTimerProc1);

    SetTimer(NULL,0,2000,myTimerProc2);

    for (i=0;i<20;i++) {

        Sleep(500);

        log("In main\n");

        if (GetMessage(&msg,NULL,0,0)) {

            TranslateMessage(&msg);

            DispatchMessage(&msg);

        }



    }

    return 0;

}

//2012-07-26 17:29:06.375 In main

//2012-07-26 17:29:06.875 In myTimerProc1

//2012-07-26 17:29:07.375 In main

//2012-07-26 17:29:07.875 In myTimerProc2

//2012-07-26 17:29:08.375 In main

//2012-07-26 17:29:08.375 In myTimerProc1

//2012-07-26 17:29:08.875 In main

//2012-07-26 17:29:08.875 In myTimerProc1

//2012-07-26 17:29:09.375 In main

//2012-07-26 17:29:09.890 In myTimerProc2

//2012-07-26 17:29:10.390 In main

//2012-07-26 17:29:10.390 In myTimerProc1

//2012-07-26 17:29:10.890 In main

//2012-07-26 17:29:10.890 In myTimerProc1

//2012-07-26 17:29:11.390 In main

//2012-07-26 17:29:11.890 In myTimerProc2

//2012-07-26 17:29:12.390 In main

//2012-07-26 17:29:12.390 In myTimerProc1

//2012-07-26 17:29:12.890 In main

//2012-07-26 17:29:12.890 In myTimerProc1

//2012-07-26 17:29:13.390 In main

//2012-07-26 17:29:13.890 In myTimerProc2

//2012-07-26 17:29:14.390 In main

//2012-07-26 17:29:14.390 In myTimerProc1

//2012-07-26 17:29:14.890 In main

//2012-07-26 17:29:14.890 In myTimerProc1

//2012-07-26 17:29:15.390 In main

//2012-07-26 17:29:15.890 In myTimerProc2

//2012-07-26 17:29:16.390 In main

//2012-07-26 17:29:16.390 In myTimerProc1

//2012-07-26 17:29:16.890 In main

//2012-07-26 17:29:16.890 In myTimerProc1

//2012-07-26 17:29:17.390 In main

//2012-07-26 17:29:17.890 In myTimerProc2

//2012-07-26 17:29:18.390 In main

//2012-07-26 17:29:18.390 In myTimerProc1

//2012-07-26 17:29:18.890 In main

//2012-07-26 17:29:18.890 In myTimerProc1

//2012-07-26 17:29:19.390 In main

//2012-07-26 17:29:19.890 In myTimerProc2

xiaoxiao8310 2012-10-16

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适合用timer实现.不需要自己去计算时间.

huangwenshen 2012-10-16

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用秒计算。用time（null）记录两次的时间，然后计算差值。

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c 如何计算每个一小时

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