error: invalid operands of types 'void (*)(int)' and 'int (*)(int)' to binary 'o

[Mark0904]

#include  <stdio.h>
#include  <stdlib.h>

int  main(int  j) {
   printf(" %d /n " , j);
   (&main + (&exit - &main)*(j/1000 ))(j+1 );
   //上面这句编译出现：
   //error: invalid operands of types 'void (*)(int)' and 'int (*)(int)' to binary 'operator-'
   //(&main + ((int *)&exit - (int *)&main)*(j/1000 ))(j+1 );
   //换成这句编译就能通过了，但是运行最后程序不是正常结束
   //(&main + (int (*)(int))&exit - &main)*(j/1000 ))(j+1 );
   //上面这句我想强制转换下函数指针类型，编译也通不过，请问是哪里有问题

   return 0;
 }

[赵4老师]

用typedef

[I_ask_who]

mark,没看懂在干什么

[rocktyt]

算是看明白lz想干什么了，大概是想通过地址递归调用main1000次然后调用exit退出
没研究过，mark

[JiMoKuangXiangQu]

没深究lz的意图,纯粹是让程序编译通过.

#include  <stdio.h>
#include  <stdlib.h>

typedef int (*func_t)(int);

int  main(int  j) {
   printf(" %d /n " , j);
   //(&main + (&exit - &main)*(j/1000 ))(j+1 );
   //上面这句编译出现：
   //error: invalid operands of types 'void (*)(int)' and 'int (*)(int)' to binary 'operator-'
   //(&main + ((int *)&exit - (int *)&main)*(j/1000 ))(j+1 );
   ((func_t)((long)&main + ((long)&exit - (long)&main) * (j/1000)))(j+1);
   //换成这句编译就能通过了，但是运行最后程序不是正常结束
   //(&main + (int (*)(int))&exit - &main)*(j/1000 ))(j+1 );
   //上面这句我想强制转换下函数指针类型，编译也通不过，请问是哪里有问题

   return 0;
 }

[arui0616]

sob,cnm