char*与bitset互相转化

[han3172700]

64位的bitset和char a[8]相互转化

[qq120848369]

看bitset的接口。

[nirvana_newbie]

你想要的是这种？

#include <iostream>
#include <bitset>
using namespace std;
int main ()
{
  bitset<4> mybits;     // mybits: 0000
  mybits.set();         // mybits: 1111
  cout << mybits << " as an integer is: " << mybits.to_ulong() << endl;
  return 0;
}

[CyberLogix]

就是位操作啊

[zhuhai__yizhi]

	long long number = 21;
	bitset<64> b1(number);

	// bitset转化为char*
	string str = b1.to_string();
	char* ch = const_cast<char*>(str.c_str());
	cout << str << endl;
	cout << ch << endl;

	// char*转化为bitset
	char* chNum = "32";
	bitset<32> b2(atoi(chNum));
	cout << b2 << endl;