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select t1.id,
t1.name,
sum(decode(t2.trans, '入', t2.num, 0)) input,
sum(decode(t2.trans, '出', t2.num, 0)) output,
sum(decode(t2.trans, '入', t2.num, 0)) -
sum(decode(t2.trans, '出', t2.num, 0)) cout
from tab_1 t1, tab_2 t2
where t1.name = t2.name
group by t1.id, t1.name