如何用数组指针传值

[皓月鸣心]

我想将数组a中的值传给数组b，但是实现不了，为什么啊？
#include <stdio.h>
fun(double*p)
{

double a[10]={0.0,1.0,2.0,3.0,4.0,5.0,6.0,7.0,8.0,9.0};
p=a;
return 0;
}

int main()
{
double b[10]={0.0};
fun(b);
printf("%f",b[5]);
return 0;
}
结果为0.0000

[max_min_]

include <stdio.h>
fun(double*p)
{

double a[10]={0.0,1.0,2.0,3.0,4.0,5.0,6.0,7.0,8.0,9.0};
//p=a; //这里只是地址操作而已
memcpy((void*)p, (void*)a, sizeof(double) * 10); //用这个试试
return 0;
}

[皓月鸣心]

果然厉害，为什么地址操作不可以，是因为分配的内存不连续吗？

[AnYidan]

引用 2 楼 u011922164 的回复:

果然厉害，为什么地址操作不可以，是因为分配的内存不连续吗？

p=a; //数组a 此时退化为指针 If the type of an expression or subexpression is ``array of T,'' for some type T, then the value of the expression is a pointer to the first object in the array, and the type of the expression is altered to ``pointer to T.'' This conversion does not take place if the expression is in the operand of the unary & operator, or of ++, --, sizeof, or as the left operand of an assignment operator or the . operator. Similarly, an expression of type ``function returning T,'' except when used as the operand of the & operator, is converted to ``pointer to function returning T.''