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#include<stdio.h>
#include<stdlib.h>
typedef struct Linked
{
char data;
struct Linked* next;
}link,*plink;
int main()
{
plink head,ptr;
char num = 10;
char len = 0;
char j = 0;
char i = 0;
plink temp,p[10];
//创建空链表,表头结点
head = (plink)malloc(sizeof(link));
head->next = NULL;
ptr = head;
//动态建立链表
while(num--)
{
ptr->next = (plink)malloc(sizeof(link));
ptr = ptr->next;
ptr->data = num;
ptr->next = NULL;
}
//打印链表各结点data值,和链表长度
ptr = head->next;
while(ptr!=NULL)
{
printf("%d ",ptr->data);
ptr = ptr->next;
len++;
}
ptr = head->next;
printf("\n len:%d\n",len); //得出len = 10,故在变量定义声明部分创建长度为10的数组。
//将链表各结点地址赋给数组P[10]
while(ptr!=NULL)
{
p[i] = ptr;
ptr = ptr->next;
}
//冒泡法根据P[i]指向结点的data值,从新排列数组p
for( i=0;i<len;i++)
for( j=0;j<len-i;j++)
{
if( p[j]->data > p[j+1]->data )
{
temp = p[j];
p[j] = p[j+1];
p[j+1] = temp;
}
}
//根据数组P,重新排列链表
i=0;
head->next = p[i];
while(p[i]->next!=NULL)
{
p[i]->next = p[i+1];
i++;
}
//打印新的链表
ptr = head->next;
while(ptr!=NULL)
{
printf("%d ",ptr->data);
ptr = ptr->next;
}
}
/*****************************************************************
* EXAMPLE 1 *
* This simple program illustrates the basic debugging features *
* of the C runtime libraries, and the kind of debug output *
* that these features generate. *
*****************************************************************/
#include <stdio.h>
#include <string.h>
#include <malloc.h>
#include <crtdbg.h>
// This routine place comments at the head of a section of debug output
void OutputHeading( const char * explanation )
{
_RPT1( _CRT_WARN, "\n\n%s:\n**************************************\
************************************\n", explanation );
}
// The following macros set and clear, respectively, given bits
// of the C runtime library debug flag, as specified by a bitmask.
#ifdef _DEBUG
#define SET_CRT_DEBUG_FIELD(a) \
_CrtSetDbgFlag((a) | _CrtSetDbgFlag(_CRTDBG_REPORT_FLAG))
#define CLEAR_CRT_DEBUG_FIELD(a) \
_CrtSetDbgFlag(~(a) & _CrtSetDbgFlag(_CRTDBG_REPORT_FLAG))
#else
#define SET_CRT_DEBUG_FIELD(a) ((void) 0)
#define CLEAR_CRT_DEBUG_FIELD(a) ((void) 0)
#endif
void main( )
{
char *p1, *p2;
_CrtMemState s1, s2, s3;
// Send all reports to STDOUT
_CrtSetReportMode( _CRT_WARN, _CRTDBG_MODE_FILE );
_CrtSetReportFile( _CRT_WARN, _CRTDBG_FILE_STDOUT );
_CrtSetReportMode( _CRT_ERROR, _CRTDBG_MODE_FILE );
_CrtSetReportFile( _CRT_ERROR, _CRTDBG_FILE_STDOUT );
_CrtSetReportMode( _CRT_ASSERT, _CRTDBG_MODE_FILE );
_CrtSetReportFile( _CRT_ASSERT, _CRTDBG_FILE_STDOUT );
// Allocate 2 memory blocks and store a string in each
p1 = malloc( 34 );
strcpy( p1, "This is the p1 string (34 bytes)." );
p2 = malloc( 34 );
strcpy( p2, "This is the p2 string (34 bytes)." );
OutputHeading(
"Use _ASSERTE to check that the two strings are identical" );
_ASSERTE( strcmp( p1, p2 ) == 0 );
OutputHeading(
"Use a _RPT macro to report the string contents as a warning" );
_RPT2( _CRT_WARN, "p1 points to '%s' and \np2 points to '%s'\n", p1, p2 );
OutputHeading(
"Use _CRTMemDumpAllObjectsSince to check the p1 and p2 allocations" );
_CrtMemDumpAllObjectsSince( NULL );
free( p2 );
OutputHeading(
"Having freed p2, dump allocation information about p1 only" );
_CrtMemDumpAllObjectsSince( NULL );
// Store a memory checkpoint in the s1 memory-state structure
_CrtMemCheckpoint( &s1 );
// Allocate another block, pointed to by p2
p2 = malloc( 38 );
strcpy( p2, "This new p2 string occupies 38 bytes.");
// Store a 2nd memory checkpoint in s2
_CrtMemCheckpoint( &s2 );
OutputHeading(
"Dump the changes that occurred between two memory checkpoints" );
if ( _CrtMemDifference( &s3, &s1, &s2 ) )
_CrtMemDumpStatistics( &s3 );
// Free p2 again and store a new memory checkpoint in s2
free( p2 );
_CrtMemCheckpoint( &s2 );
OutputHeading(
"Now the memory state at the two checkpoints is the same" );
if ( _CrtMemDifference( &s3, &s1, &s2 ) )
_CrtMemDumpStatistics( &s3 );
strcpy( p1, "This new p1 string is over 34 bytes" );
OutputHeading( "Free p1 after overwriting the end of the allocation" );
free( p1 );
// Set the debug-heap flag so that freed blocks are kept on the
// linked list, to catch any inadvertent use of freed memory
SET_CRT_DEBUG_FIELD( _CRTDBG_DELAY_FREE_MEM_DF );
p1 = malloc( 10 );
free( p1 );
strcpy( p1, "Oops" );
OutputHeading( "Perform a memory check after corrupting freed memory" );
_CrtCheckMemory( );
// Use explicit calls to _malloc_dbg to save file name and line number
// information, and also to allocate Client type blocks for tracking
p1 = _malloc_dbg( 40, _NORMAL_BLOCK, __FILE__, __LINE__ );
p2 = _malloc_dbg( 40, _CLIENT_BLOCK, __FILE__, __LINE__ );
strcpy( p1, "p1 points to a Normal allocation block" );
strcpy( p2, "p2 points to a Client allocation block" );
// You must use _free_dbg to free a Client block
OutputHeading(
"Using free( ) to free a Client block causes an assertion failure" );
free( p1 );
free( p2 );
p1 = malloc( 10 );
OutputHeading( "Examine outstanding allocations (dump memory leaks)" );
_CrtDumpMemoryLeaks( );
// Set the debug-heap flag so that memory leaks are reported when
// the process terminates. Then, exit.
OutputHeading( "Program exits without freeing a memory block" );
SET_CRT_DEBUG_FIELD( _CRTDBG_LEAK_CHECK_DF );
}
Output
Use _ASSERTE to check that the two strings are identical:
**************************************************************************
C:\DEV\EXAMPLE1.C(56) : Assertion failed: strcmp( p1, p2 ) == 0
Use a _RPT macro to report the string contents as a warning:
**************************************************************************
p1 points to 'This is the p1 string (34 bytes).' and
p2 points to 'This is the p2 string (34 bytes).'
Use _CRTMemDumpAllObjectsSince to check the p1 and p2 allocations:
**************************************************************************
Dumping objects ->
{13} normal block at 0x00660B5C, 34 bytes long
Data: <This is the p2 s> 54 68 69 73 20 69 73 20 74 68 65 20 70 32 20 73
{12} normal block at 0x00660B10, 34 bytes long
Data: <This is the p1 s> 54 68 69 73 20 69 73 20 74 68 65 20 70 31 20 73
Object dump complete.
Having freed p2, dump allocation information about p1 only:
**************************************************************************
Dumping objects ->
{12} normal block at 0x00660B10, 34 bytes long
Data: <This is the p1 s> 54 68 69 73 20 69 73 20 74 68 65 20 70 31 20 73
Object dump complete.
Dump the changes that occurred between two memory checkpoints:
**************************************************************************
0 bytes in 0 Free Blocks.
38 bytes in 1 Normal Blocks.
0 bytes in 0 CRT Blocks.
0 bytes in 0 IgnoreClient Blocks.
0 bytes in 0 (null) Blocks.
Largest number used: 4 bytes.
Total allocations: 38 bytes.
Now the memory state at the two checkpoints is the same:
**************************************************************************
Free p1 after overwriting the end of the allocation:
**************************************************************************
memory check error at 0x00660B32 = 0x73, should be 0xFD.
memory check error at 0x00660B33 = 0x00, should be 0xFD.
DAMAGE: after Normal block (#12) at 0x00660B10.
Perform a memory check after corrupting freed memory:
**************************************************************************
memory check error at 0x00660B10 = 0x4F, should be 0xDD.
memory check error at 0x00660B11 = 0x6F, should be 0xDD.
memory check error at 0x00660B12 = 0x70, should be 0xDD.
memory check error at 0x00660B13 = 0x73, should be 0xDD.
memory check error at 0x00660B14 = 0x00, should be 0xDD.
DAMAGE: on top of Free block at 0x00660B10.
DAMAGED located at 0x00660B10 is 10 bytes long.
Using free( ) to free a Client block causes an assertion failure:
**************************************************************************
dbgheap.c(1039) : Assertion failed: pHead->nBlockUse == nBlockUse
Examine outstanding allocations (dump memory leaks):
**************************************************************************
Detected memory leaks!
Dumping objects ->
{18} normal block at 0x00660BE4, 10 bytes long
Data: < > CD CD CD CD CD CD CD CD CD CD
Object dump complete.
Program exits without freeing a memory block:
**************************************************************************
Detected memory leaks!
Dumping objects ->
{18} normal block at 0x00660BE4, 10 bytes long
Data: < > CD CD CD CD CD CD CD CD CD CD
Object dump complete.
//假设带表头结点的单向链表头指针为head,试编写一个算法将值为5的结点插入到连接表的第k个结点前,删除第k个节点,并对该链表进行排序。
#include <stdio.h>
#include <stdlib.h>
#include <malloc.h>
#include <time.h>
struct NODE {
int data;
struct NODE *next;
} H,*head,*p,*q,*s1,*s2,*s3,*s4,*s;
int i,j,k,n,t,m;
int main() {
srand(time(NULL));
//填写头节点数据
H.data=-1;
H.next=NULL;
head=&H;
//创建10个节点的单链表
p=head;
for (i=0;i<10;i++) {
q=(struct NODE *)malloc(sizeof(struct NODE));
if (NULL==q) return 1;
q->data=rand()%100;//填写0..99的随机值
q->next=NULL;
p->next=q;
p=q;
}
//输出整个单链表
s=head->next;
while (1) {
if (NULL==s) {
printf("\n");
break;
}
printf("%02d->",s->data);
s=s->next;
}
//将值为5的结点插入到单链表的第k个结点前
k=3;
n=0;
p=head;
while (1) {
if (NULL==p) {
break;
}
n++;
if (k==n) {
q=(struct NODE *)malloc(sizeof(struct NODE));
if (NULL==q) return 1;
q->data=5;
q->next=p->next;
p->next=q;
break;
}
p=p->next;
}
//输出整个单链表
s=head->next;
while (1) {
if (NULL==s) {
printf("\n");
break;
}
printf("%02d->",s->data);
s=s->next;
}
//删除第k个节点
k=5;
n=0;
p=head;
while (1) {
if (NULL==p) {
break;
}
n++;
if (k==n) {
q=p->next;
if (q) {
p->next=q->next;
free(q);
}
break;
}
p=p->next;
}
//输出整个单链表
s=head->next;
while (1) {
if (NULL==s) {
printf("\n");
break;
}
printf("%02d->",s->data);
s=s->next;
}
//从小到大排序
for (p=head;p!=NULL && p->next!=NULL;p=p->next) {
for (q=p->next;q!=NULL && q->next!=NULL;q=q->next) {
if (p->next->data > q->next->data) {
//交换data
// printf("swap %02d %02d\n",p->next->data,q->next->data);
// t=p->next->data;p->next->data=q->next->data;q->next->data=t;
//或者
//交换next
// printf("swap %02d %02d\n",p->next->data,q->next->data);
s1=p->next;
s2=p->next->next;
s3=q->next;
s4=q->next->next;
if (s2!=s3) {
p->next=s3;
s3->next=s2;
q->next=s1;
s1->next=s4;
} else {
p->next=s3;
s3->next=s1;
q=s3;
s1->next=s4;
}
//输出整个单链表
// s=head->next;
// while (1) {
// if (NULL==s) {
// printf("\n");
// break;
// }
// printf("%02d->",s->data);
// s=s->next;
// }
// getchar();
}
}
}
//输出整个单链表
s=head->next;
while (1) {
if (NULL==s) {
printf("\n");
break;
}
printf("%02d->",s->data);
s=s->next;
}
//将单链表中前 m 个结点和后 n 个结点进行互换,m+n为链表总长10
m=4;
n=6;
k=0;
p=head;
while (1) {
if (NULL==p) {
break;
}
k++;
if (m+1==k) {
q=p;
}
s=p;
p=p->next;
}
s1=head->next;
head->next=q->next;
s->next=s1;
q->next=NULL;
//输出整个单链表
s=head->next;
while (1) {
if (NULL==s) {
printf("\n");
break;
}
printf("%02d->",s->data);
s=s->next;
}
//释放所有节点
p=head->next;
while (1) {
if (NULL==p) {
break;
}
q=p->next;
free(p);
p=q;
}
return 0;
}
//18->94->58->17->27->20->43->57->75->78->
//18->94->05->58->17->27->20->43->57->75->78->
//18->94->05->58->27->20->43->57->75->78->
//05->18->20->27->43->57->58->75->78->94->
//43->57->58->75->78->94->05->18->20->27->
//
//将链表各结点地址赋给数组P[10]
while(ptr!=NULL)
{
p[i] = ptr;
ptr = ptr->next;
}
循环中i无变化,所以仅仅为p[0]赋值
考虑改为:
while(ptr!=NULL) {
p[i++] = ptr;
ptr = ptr->next;
}
2
//根据数组P,重新排列链表
i=0;
head->next = p[i];
while(p[i]->next!=NULL)
{
p[i]->next = p[i+1];
i++;
}
因为数组已排序,原来的结点顺序已打乱,尾结点可能出现在数组的任意位置,所以这样是不对的
考虑改为
//根据数组P,重新排列链表
i=0;
head->next = p[i];
while(i < 9) {
p[i]->next = p[i+1];
i++;
}
p[i]->next = NULL;