大神帮忙看下这个程序，运行为什么是这个样子

[u012496871]

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main()
{
int num = 0, num1 = 0, row = 0, col = 0, mox = 0, moy = 0, in = 0, in1 = 0, min = 0, max = 0;
srand(time(0));
printf("请输入次数: ");
scanf("%d", &num);
printf("***\n***\n***\n");//地图
do
{
printf("请输入锤子坐标: ");
scanf("%d%d", &in, &in1);
}while(in < 1 || in > 3 || in1 < 1 || in1 > 3);
mox = rand() % 3 + 1;
moy = rand() % 3 + 1;
for (num1 = 1; num1 <= num; num1++)
{
for(row = 0; row <= 2; row++)
{
for (col = 0;col <= 2;col++)
{
if ((in == row) && (in1 == col))
{
printf("O");
}
else if ((mox == row) && (moy == col))
{
printf("X");
}
else
{
printf("*");
}
printf("打中了");
min++;
}
printf("没打中");
max++;
}
printf("打中%d次，没打中%d次", min, max);
}
printf("\n");
return 0;
}


打印出来的结果是：
请输入次数: 2
***
***
***
请输入锤子坐标: 2 2
*打中了*打中了*打中了没打中*打中了*打中了*打中了没打中*打中了X打中了O打中了没打中打中9次，没打中3次*打中了*打中了*打中了没打中*打中了*打中了*打中了没打中*打中了X打中了O打中了没打中打中18次，没打中6次

[百曉生]

能简单描述一下程序的功能吗？

[cyd54454]

发帖的时候，用一下代码功能，用下TAB呗...看的头大

[C_Scholar]

我这里有一份 ，你照着理下逻辑 ！ #include <stdio.h> #include <stdlib.h> #include <time.h> int main() { int times = 0/*游戏次数*/, mousey = 0/*老鼠所在行号*/, mousex = 0/*老鼠所在列号*/, posy = 0/*锤子所在行号*/, posx = 0/*锤子所在列号*/, hits = 0/*打中次数*/, missed = 0/*错过次数*/; int num = 0, row = 0, col = 0; srand(time(0)); //获得游戏次数 printf("请输入次数："); scanf("%d", ×); //打印地图 printf("***\n***\n***\n"); //游戏过程 for (num = 1;num <= times;num++) { //获得老鼠和锤子的位置 mousey = rand() % 3 + 1; mousex = rand() % 3 + 1; do { printf("请输入锤子所在的位置："); scanf("%d %d", &posy, &posx); } while (posy < 1 || posy > 3 || posx < 1 || posx > 3); //修改打中和错过的个数 if (mousey == posy && mousex == posx) { hits++; } else { missed++; } //打印地图 for (row = 1;row <= 3;row++) { for (col = 1;col <= 3;col++) { if (row == posy && col == posx) { printf("O"); } else if (row == mousey && col == mousex) { printf("X"); } else { printf("*"); } } printf("\n"); } //提示是否打中 if (mousey == posy && mousex == posx) { printf("打中了\n"); } else { printf("没打中\n"); } //打印总成绩 printf("打中%d次，错过%d次\n", hits, missed); } return 0; }