求指教！为什么这个程序vc可以输出结果在Dev-cpp运行到scanf那里就不走了

明朝一典史 2014-08-13 09:34:37

#include<stdio.h>
#include<math.h>
int main()
{
unsigned int a=0;
printf("Enter a postive integer: ");
scanf("%d",&a);

int i=1,
j=1,
n=0,
sum=0,
c=a,
b=0;
do
{
n=pow(10,i);
b=(c%n)/(n/10);
c-=b*(n/10);
i++;
}
while(c!=0);

c=a;
do
{
n=pow(10,j);
b=(c%n)/(n/10);
c-=b*(n/10);
sum+=b*pow(10,i-2);
j++;
i--;
}
while(i>=0);
printf("The number %d reserved is %d rebmun ehT.",a,sum);
return 0;

}

编译器为vc++6。0
Dev-c++5.4.1

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赵4老师 2014-08-14

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pow Calculates x raised to the power of y. double pow( double x, double y ); Routine Required Header Compatibility pow <math.h> ANSI, Win 95, Win NT For additional compatibility information, see Compatibility in the Introduction. Libraries LIBC.LIB Single thread static library, retail version LIBCMT.LIB Multithread static library, retail version MSVCRT.LIB Import library for MSVCRT.DLL, retail version Return Value pow returns the value of xy. No error message is printed on overflow or underflow. Values of x and y Return Value of pow x < > 0 and y = 0.0 1 x = 0.0 and y = 0.0 1 x = 0.0 and y < 0 INF Parameters x Base y Exponent Remarks The pow function computes x raised to the power of y. pow does not recognize integral floating-point values greater than 264, such as 1.0E100. Example /* POW.C * */ #include <math.h> #include <stdio.h> void main( void ) { double x = 2.0, y = 3.0, z; z = pow( x, y ); printf( "%.1f to the power of %.1f is %.1f\n", x, y, z ); } Output 2.0 to the power of 3.0 is 8.0 Floating-Point Support Routines See Also exp, log, sqrt http://bbs.csdn.net/topics/390676437

明朝一典史 2014-08-14

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引用 13 楼 brookmill 的回复:

我觉得可能是unsigned int和%d不匹配造成的问题。楼主可以试试这两个改动： 1. unsigned int a=0; scanf("%u",&a); 2. int a=0; scanf("%d",&a); 一般情况下unsigned int和%d混用都问题不大，dev-cpp不知道有什么不一样。顺便说一句，我刚入行的时候曾经这么干过： short a; scanf("%d", &a); 结果就把栈弄崩了，自己还不知道是怎么回事。从那以后就觉得scanf太危险了（其实该说指针太危险了）

非常感谢不过我试过了不是这个原因原因是就是上面所说的还是很感谢

明朝一典史 2014-08-14

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引用 14 楼 zhao4zhong1 的回复:

pow Calculates x raised to the power of y. double pow( double x, double y ); Routine Required Header Compatibility pow <math.h> ANSI, Win 95, Win NT For additional compatibility information, see Compatibility in the Introduction. Libraries LIBC.LIB Single thread static library, retail version LIBCMT.LIB Multithread static library, retail version MSVCRT.LIB Import library for MSVCRT.DLL, retail version Return Value pow returns the value of xy. No error message is printed on overflow or underflow. Values of x and y Return Value of pow x < > 0 and y = 0.0 1 x = 0.0 and y = 0.0 1 x = 0.0 and y < 0 INF Parameters x Base y Exponent Remarks The pow function computes x raised to the power of y. pow does not recognize integral floating-point values greater than 264, such as 1.0E100. Example /* POW.C * */ #include <math.h> #include <stdio.h> void main( void ) { double x = 2.0, y = 3.0, z; z = pow( x, y ); printf( "%.1f to the power of %.1f is %.1f\n", x, y, z ); } Output 2.0 to the power of 3.0 is 8.0 Floating-Point Support Routines See Also exp, log, sqrt http://bbs.csdn.net/topics/390676437

非常感谢！！我看了Dev有关math.h里面有关pow的定义发现pow的参数必须是float 或者 long double型如下： /* 7.12.7.4 The pow functions. Double in C89 */ extern float __cdecl powf (float, float); #ifndef __NO_INLINE__ __CRT_INLINE float __cdecl powf (float x, float y) {return (float) pow (x, y);} #endif extern long double __cdecl powl (long double, long double); 改过来就好了

brookmill 2014-08-14

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我觉得可能是unsigned int和%d不匹配造成的问题。楼主可以试试这两个改动： 1. unsigned int a=0; scanf("%u",&a); 2. int a=0; scanf("%d",&a); 一般情况下unsigned int和%d混用都问题不大，dev-cpp不知道有什么不一样。顺便说一句，我刚入行的时候曾经这么干过： short a; scanf("%d", &a); 结果就把栈弄崩了，自己还不知道是怎么回事。从那以后就觉得scanf太危险了（其实该说指针太危险了）