为什么写链表出现assignment from incompatible pointer type

[楚江课的救赎]

用c写了个链表 gcc编译直接报warming： assignment from incompatible pointer type
帮忙看下原因。

typedef unsigned long DWORD;  //4Bytes
typedef unsigned short WORD;  //2Bytes
typedef unsigned int UINT;    //通常4Bytes
typedef signed char CHAR;     // 1Bytes
typedef unsigned char BYTE;    //1Bytes

typedef struct TS_Node{
      BYTE acDate[250];
      UINT uTS_Length;
    struct TS_Node*next;
}TS_Node_S;

/*
用于存储pid相同的TS包,bContain标志位用于判断当前链表中是否存储过带有效净荷的TS
*/
typedef  struct TS_Store{
      UINT uPid;
      UINT uContain;
	  struct TS_Node_S*psHead;
	  struct TS_Node_S*psTail;
}TS_Store_S;

/*
将TS_Store_S链接起来
*/
typedef struct TS_Store_All{
        TS_Store_S  sTS_Store;
        struct TS_Store_All  *psNext;
}TS_Store_All_S;
/////////////////////////////////////////////////////////////////////////////////
if (0 == (temp->sTS_Store). uContain) {
TS_Node_S *psTS_Node = (TS_Node_S*)malloc(sizeof(TS_Node_S));
 memcpy(psTS_Node->acDate,pTS_Buffer,uTS_Buffer_Length);
 psTS_Node->uTS_Length = uTS_Buffer_Length;
if(NULL == (temp->sTS_Store).psHead)
  {
(temp->sTS_Store).psHead = psTS_Node;       //warning: assignment from incompatible pointer type
(temp->sTS_Store).psTail = psTS_Node;          //warning: assignment from incompatible pointer type
(temp->sTS_Store).uContain = 1;
return 0;
}
				else
				{
			                    TS_Node_S *psTS_Node_Insert = (temp->sTS_Store).psTail;
				psTS_Node_Insert->next=psTS_Node;
				(temp->sTS_Store).psTail = psTS_Node_Insert->next;
				(temp->sTS_Store).uContain = 1;
				return 0;
					
					
			    }
			}

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