如何将百度地图获取的经纬度坐标转换为GPS坐标

[jliu_10]

最近在做一个百度地图的项目，但是需要将获取的百度地图的坐标通过IOS SDK坐标转换接口转换为GPS经纬度坐标，不知道使用什么方法，求大神们帮帮忙！

[rightorwrong]

只有把gps转成百度坐标

[miss_chalk]

//  把火星坐标转换成百度坐标
-(CLLocationCoordinate2D)hhTrans_bdGPS:(CLLocationCoordinate2D)fireGps
{
    
    CLLocationCoordinate2D bdGps;
    
    double huo_x=fireGps.longitude;
    
    double huo_y=fireGps.latitude;
    
    double z = sqrt(huo_x * huo_x + huo_y * huo_y) + 0.00002 * sin(huo_y * x_pi);
    
    double theta = atan2(huo_y, huo_x) + 0.000003 * cos(huo_x * x_pi);
    
    bdGps.longitude = z * cos(theta) + 0.0065;
    
    bdGps.latitude = z * sin(theta) + 0.006;
    
    return bdGps;
    
}

// 百度转火星
-(CLLocationCoordinate2D)hhTrans_GCGPS:(CLLocationCoordinate2D)baiduGps
{
    
    CLLocationCoordinate2D googleGps;
    
    double bd_x=baiduGps.longitude - 0.0065;
    
    double bd_y=baiduGps.latitude - 0.006;
    
    double z = sqrt(bd_x * bd_x + bd_y * bd_y) - 0.00002 * sin(bd_y * x_pi);
    
    double theta = atan2(bd_y, bd_x) - 0.000003 * cos(bd_x * x_pi);
    
    googleGps.longitude = z * cos(theta);
    
    googleGps.latitude = z * sin(theta);
    
    return googleGps;
    
}

请叫我雷锋。

[miss_chalk]

[qq_32084645]

大神 x_pi 值时多少啊

[啤丶酒]

引用 2 楼 sijiazhentan 的回复:

//  把火星坐标转换成百度坐标
-(CLLocationCoordinate2D)hhTrans_bdGPS:(CLLocationCoordinate2D)fireGps
{
    
    CLLocationCoordinate2D bdGps;
    
    double huo_x=fireGps.longitude;
    
    double huo_y=fireGps.latitude;
    
    double z = sqrt(huo_x * huo_x + huo_y * huo_y) + 0.00002 * sin(huo_y * x_pi);
    
    double theta = atan2(huo_y, huo_x) + 0.000003 * cos(huo_x * x_pi);
    
    bdGps.longitude = z * cos(theta) + 0.0065;
    
    bdGps.latitude = z * sin(theta) + 0.006;
    
    return bdGps;
    
}

// 百度转火星
-(CLLocationCoordinate2D)hhTrans_GCGPS:(CLLocationCoordinate2D)baiduGps
{
    
    CLLocationCoordinate2D googleGps;
    
    double bd_x=baiduGps.longitude - 0.0065;
    
    double bd_y=baiduGps.latitude - 0.006;
    
    double z = sqrt(bd_x * bd_x + bd_y * bd_y) - 0.00002 * sin(bd_y * x_pi);
    
    double theta = atan2(bd_y, bd_x) - 0.000003 * cos(bd_x * x_pi);
    
    googleGps.longitude = z * cos(theta);
    
    googleGps.latitude = z * sin(theta);
    
    return googleGps;
    
}

请叫我雷锋。

安卓版怎么写啊

[染上空白]

2L好牛啊，果断能用感谢大神