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SELECT agreement_projectid
FROM table_name
GROUP BY agreement_projectid
HAVING MAX(agreement_project_error) = 0;
--按照agreement_projectid分组 取agreement_project_error最大值为0的数据
--最大值为0 则全部为0
SELECT DISTINCT agreement_projectid FROM table_name WHERE agreement_project_error = 1;
--存在agreement_project_error = 1的数据都列出来 然后去重