关于二维指针和字符串的问题 求帮忙!!!!!!

Van_Le 2015-09-01 01:42:10
//请大家看看 有什么问题 想了好久 没找到 谢谢!!

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<memory.h>
int GetApartString(const char * p,char ** p1,int* num)
{
if (p == NULL&&p1 == NULL)
printf("指针错误!!");
int len = strlen(p);
char* p2 = p;
for (int i = 0;; i++)
{
if (strchr(p2, ',') != NULL)
{
char * p3=strchr(p2, ',');
for (int j = 0; j <=(p3 - p2); j++)//赋值
{
if (j == (p3 - p2))
*(&p1[i][j]) = '\0';//这里有问题 :字符串读取出问题
else
*(&p1[i][j]) = *(p2 + j);
}
// memcpy(&p1[i][0], p2, (p3 - p2));
p2 = strchr(p2, ',')+1;
(*num)++;
}
break;
}
}
void main()
{
char pp1[] = "abcdef, acccd,eeee, aaaa, e3eeeee, sssss,";
printf("%s", pp1);
char pp2[10][100] = { { "rr" } };
printf("%c", pp2[0][0]);
char **ppp2 = pp2;
int a = 0;
int *num = &a;
GetApartString(pp1, ppp2,num);

}
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赵4老师 2015-09-01
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仅供参考:
#include <stdio.h>
#include <string.h>
char string[80];
char seps1[3];
char seps2[3];
char *token;
char *zzstrtok (
    char *string,
    const char *control1,//连续出现时视为中间夹空token
    const char *control2 //连续出现时视为中间无空token
    )
{
    unsigned char *str;
    const unsigned char *ctrl1 = (const unsigned char *)control1;
    const unsigned char *ctrl2 = (const unsigned char *)control2;
    unsigned char map1[32],map2[32];
    static char *nextoken;
    static char flag=0;
    unsigned char c;
    int L;

    memset(map1,0,32);
    memset(map2,0,32);
    do {
        map1[*ctrl1 >> 3] |= (1 << (*ctrl1 & 7));
    } while (*ctrl1++);
    do {
        map2[*ctrl2 >> 3] |= (1 << (*ctrl2 & 7));
    } while (*ctrl2++);

    if (string) {
        if (control2[0]) {
            L=strlen(string);
            while (1) {
                c=string[L-1];
                if (map2[c >> 3] & (1 << (c & 7))) {
                    L--;
                    string[L]=0;
                } else break;
            }
        }
        if (control1[0]) {
            L=strlen(string);
            c=string[L-1];
            if (map1[c >> 3] & (1 << (c & 7))) {
                string[L]=control1[0];
                string[L+1]=0;
            }
        }
        str=(unsigned char *)string;
    }
    else str=(unsigned char *)nextoken;

    string=(char *)str;
    while (1) {
        if (0==flag) {
            if (!*str) break;
            if (map1[*str >> 3] & (1 << (*str & 7))) {
                *str=0;
                str++;
                break;
            } else if (map2[*str >> 3] & (1 << (*str & 7))) {
                string++;
                str++;
            } else {
                flag=1;
                str++;
            }
        } else if (1==flag) {
            if (!*str) break;
            if (map1[*str >> 3] & (1 << (*str & 7))) {
                *str=0;
                str++;
                flag=0;
                break;
            } else if (map2[*str >> 3] & (1 << (*str & 7))) {
                *str=0;
                str++;
                flag=2;
                break;
            } else str++;
        } else {//2==flag
            if (!*str) return NULL;
            if (map1[*str >> 3] & (1 << (*str & 7))) {
                str++;
                string=(char *)str;
                flag=0;
            } else if (map2[*str >> 3] & (1 << (*str & 7))) {
                str++;
                string=(char *)str;
            } else {
                string=(char *)str;
                str++;
                flag=1;
            }
        }
    }
    nextoken=(char *)str;

    if (string==(char *)str) return NULL;
    else             return string;
}
void main()
{
   strcpy(string,"A \tstring\t\tof ,,tokens\n\nand some  more tokens, ");
   strcpy(seps1,",\n");strcpy(seps2," \t");
   printf("\n[%s]\nTokens:\n",string);
   token=zzstrtok(string,seps1,seps2);
   while (token!=NULL) {
      printf(" <%s>",token);
      token=zzstrtok(NULL,seps1,seps2);
   }

   strcpy(string,"1234| LIYI|China | 010 |201110260000|OK");
   strcpy(seps1,"|");strcpy(seps2," ");
   printf("\n[%s]\nTokens:\n",string);
   token=zzstrtok(string,seps1,seps2);
   while (token!=NULL) {
      printf(" <%s>",token);
      token=zzstrtok(NULL,seps1,seps2);
   }

   strcpy(string,"1234|LIYI||010|201110260000|OK");
   strcpy(seps1,"");strcpy(seps2,"|");
   printf("\n[%s]\nTokens:\n",string);
   token=zzstrtok(string,seps1,seps2);
   while (token!=NULL) {
      printf(" <%s>",token);
      token=zzstrtok(NULL,seps1,seps2);
   }

   strcpy(string,"1234|LIYI||010|201110260000|OK");
   strcpy(seps1,"|");strcpy(seps2,"");
   printf("\n[%s]\nTokens:\n",string);
   token=zzstrtok(string,seps1,seps2);
   while (token!=NULL) {
      printf(" <%s>",token);
      token=zzstrtok(NULL,seps1,seps2);
   }

   strcpy(string,"a");
   strcpy(seps1,",");strcpy(seps2,"");
   printf("\n[%s]\nTokens:\n",string);
   token=zzstrtok(string,seps1,seps2);
   while (token!=NULL) {
      printf(" <%s>",token);
      token=zzstrtok(NULL,seps1,seps2);
   }

   strcpy(string,"a,b");
   strcpy(seps1,",");strcpy(seps2,"");
   printf("\n[%s]\nTokens:\n",string);
   token=zzstrtok(string,seps1,seps2);
   while (token!=NULL) {
      printf(" <%s>",token);
      token=zzstrtok(NULL,seps1,seps2);
   }

   strcpy(string,"a,,b");
   strcpy(seps1,",");strcpy(seps2,"");
   printf("\n[%s]\nTokens:\n",string);
   token=zzstrtok(string,seps1,seps2);
   while (token!=NULL) {
      printf(" <%s>",token);
      token=zzstrtok(NULL,seps1,seps2);
   }

   strcpy(string,",a");
   strcpy(seps1,",");strcpy(seps2,"");
   printf("\n[%s]\nTokens:\n",string);
   token=zzstrtok(string,seps1,seps2);
   while (token!=NULL) {
      printf(" <%s>",token);
      token=zzstrtok(NULL,seps1,seps2);
   }

   strcpy(string,"a,");
   strcpy(seps1,",");strcpy(seps2,"");
   printf("\n[%s]\nTokens:\n",string);
   token=zzstrtok(string,seps1,seps2);
   while (token!=NULL) {
      printf(" <%s>",token);
      token=zzstrtok(NULL,seps1,seps2);
   }

   strcpy(string,",a,,b");
   strcpy(seps1,",");strcpy(seps2,"");
   printf("\n[%s]\nTokens:\n",string);
   token=zzstrtok(string,seps1,seps2);
   while (token!=NULL) {
      printf(" <%s>",token);
      token=zzstrtok(NULL,seps1,seps2);
   }

   strcpy(string,",,a,,b,,");
   strcpy(seps1,",");strcpy(seps2,"");
   printf("\n[%s]\nTokens:\n",string);
   token=zzstrtok(string,seps1,seps2);
   while (token!=NULL) {
      printf(" <%s>",token);
      token=zzstrtok(NULL,seps1,seps2);
   }

   strcpy(string,",");
   strcpy(seps1,",");strcpy(seps2,"");
   printf("\n[%s]\nTokens:\n",string);
   token=zzstrtok(string,seps1,seps2);
   while (token!=NULL) {
      printf(" <%s>",token);
      token=zzstrtok(NULL,seps1,seps2);
   }

   strcpy(string,",,");
   strcpy(seps1,",");strcpy(seps2,"");
   printf("\n[%s]\nTokens:\n",string);
   token=zzstrtok(string,seps1,seps2);
   while (token!=NULL) {
      printf(" <%s>",token);
      token=zzstrtok(NULL,seps1,seps2);
   }

   strcpy(string,",,,");
   strcpy(seps1,",");strcpy(seps2," ");
   printf("\n[%s]\nTokens:\n",string);
   token=zzstrtok(string,seps1,seps2);
   while (token!=NULL) {
      printf(" <%s>",token);
      token=zzstrtok(NULL,seps1,seps2);
   }
}
//
//[A      string          of ,,tokens
//
//and some  more tokens,]
//Tokens:
// <A>, <string>, <of>, <>, <tokens>, <>, <and>, <some>, <more>, <tokens>, <>,
//[1234| LIYI|China | 010 |201110260000|OK]
//Tokens:
// <1234>, <LIYI>, <China>, <010>, <201110260000>, <OK>,
//[1234|LIYI||010|201110260000|OK]
//Tokens:
// <1234>, <LIYI>, <010>, <201110260000>, <OK>,
//[1234|LIYI||010|201110260000|OK]
//Tokens:
// <1234>, <LIYI>, <>, <010>, <201110260000>, <OK>,
//[a]
//Tokens:
// <a>,
//[a,b]
//Tokens:
// <a>, <b>,
//[a,,b]
//Tokens:
// <a>, <>, <b>,
//[,a]
//Tokens:
// <>, <a>,
//[a,]
//Tokens:
// <a>, <>,
//[,a,,b]
//Tokens:
// <>, <a>, <>, <b>,
//[,,a,,b,,]
//Tokens:
// <>, <>, <a>, <>, <b>, <>, <>,
//[,]
//Tokens:
// <>, <>,
//[,,]
//Tokens:
// <>, <>, <>,
//[,,,]
//Tokens:
// <>, <>, <>, <>,
lin5161678 2015-09-01
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数组是数组 指针是指针 别把数组当成指针 char arr[3][4]; char** p = arr; 是完全错误的
二班的码农 2015-09-01
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静态二维数组在数据储存上元素内存地址空间是连续的,其实就是一维数组,只不过逻辑结构是二维的,所以不能将二维数组传给二级指针。楼主可以将二维数组强制转换成一级指针传给一级指针,但这样的话,在子函数访问这个一级指针,只能通过长宽计算偏移量来访问 直接在形参中声明二维数组就行,char strs[][100]; 第一维长度可以忽略 还可以通过定义数组指针实现,char (*strs)[100];
Van_Le 2015-09-01
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主要问题是 我用二级指针当函数参数 用二维数组名当实参时 函数中的二级指针 却是空 或者读不出来
宋寒松 2015-09-01
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字符串拆分,可以参考以下的做法:

#include<stdio.h>
#include<string.h>

int split_string(char* str, const char* delims, char** strs, int w)
{
    char* result = NULL;
    int i = 0;

    result = strtok(str, delims);
    while(result != NULL){
        strcpy((char*)((int)strs + i * w), result);
        i++;
        result = strtok(NULL, delims);
    }

    return i;
}

int main(int argc, char* argv[])
{
    char str[] = "abcdef,acccd,eeee,aaaa,e3eeeee,sssss";
    char strs[10][100];
    int n;
    int i;

    n = split_string(str, ",", (char**)strs, 100);
    for(i = 0; i < n; i++){
        printf("%s\n", strs[i]);
    }
}

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