[C#] Newtonsoft.Json.dll解析json实例

2015-09-29 04:28:40 513 阅读 AI 写同款 · GEO 优化AI 选题数据监测一键分发 ›

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C# 新手项目学习5 --Newtonsoft.Json Json解析 JSON解析用Newtonsoft.Json.dll 下载 http://json.codeplex.com/ 阅读详情

我刚接触[C#] Newtonsoft.Json.dll解析json，看教程做但是不够详细，希望有人能帮帮我，我是把代码写完了，也没有错误，只是教程上没说怎么添加控件，我逐个拖进去，做后运行，但是程序没有应，无法运行，也没给任何提示，有人可以教教我吗？谢谢啦。
教程链接：Newtonsoft.Json.dll解析json实例 - PHP、C#/学习-356网站建设交流社区
http://bbs.356web.com/thread-322-1-1.html

using System;

using System.Collections.Generic;

using System.ComponentModel;

using System.Data;

using System.Drawing;

using System.Linq;

using System.Text;

using System.Windows.Forms;

using System.IO;

using Newtonsoft.Json;

using Newtonsoft.Json.Linq;



namespace JsonTest

{

    public partial class Form1 : Form

    {

        public Form1()

        {

            InitializeComponent();

            ReadTxt();

        }



        private void button1_Click(object sender, EventArgs e)

        {

            ReadJson();

        }



        List<User> UserList;

        public void ReadJson()

        {

            string UsersInfo = textBox1.Text;

            if (UsersInfo == "")

            {

                MessageBox.Show("没有找到需要解析的数据！");

                return;

            }

            UserList = new List<User>();           

            JObject jsonObj = JObject.Parse(UsersInfo);

            JArray UserJa = JArray.Parse(jsonObj["Users"].ToString());            

            for (int i = 0; i < UserJa.Count; i++)

            {

                User user = new User();

                

                user.Username = UserJa[i]["Username"].ToString();

                user.Stu_number = UserJa[i]["Stu_number"].ToString();

                user.Ssd = UserJa[i]["ssd"].ToString();

                user.Key = UserJa[i]["Key"].ToString();

                user.AreaId = UserJa[i]["areaId"].ToString();

                user.Number = UserJa[i]["number"].ToString();

                UserList.Add(user);



                ListViewItem lvi = new ListViewItem(user.Username);              

                lvi.SubItems.Add(user.Stu_number);

                lvi.SubItems.Add(user.Ssd);

                lvi.SubItems.Add(user.Key);

                lvi.SubItems.Add(user.AreaId);

                lvi.SubItems.Add(user.Number);



                this.listView1.Items.Add(lvi); 

                

            }



            label1.Text = UserList[0].Username + "   " + UserList[0].Stu_number + "  " + UserList[0].Ssd + "  " + UserList[0].Key;//你想获取某一个值用这种方法显示

        }



        /// <summary>

        /// 读取存放json数据的Txt文件

        /// </summary>

        public void ReadTxt()

        {

            string strLine;

            string path = Application.StartupPath + "//UserInfo.txt";

            if(!File.Exists(path))

            {

                MessageBox.Show("指定文件不存在！");

                return;

            }

            FileStream fs = new FileStream(path, FileMode.Open);

            

            StreamReader sr = new StreamReader(fs, System.Text.Encoding.GetEncoding("gb2312"));

            strLine = sr.ReadLine();

            while (strLine != null)

            {              

                textBox1.Text = textBox1.Text+strLine;

                strLine = sr.ReadLine();

            }          

        }       

    }

}

using System;

using System.Collections.Generic;

using System.Linq;

using System.Text;



namespace JsonTest

{

    class User

    {

        string username;

        string stu_number;

        string ssd;

        string key;

        string areaId;

        string number;

        public string Username

        {

            get { return username; }

            set { username = value; }

        }        

        public string Stu_number

        {

            get { return stu_number; }

            set { stu_number = value; }

        }              

        public string Ssd

        {

            get { return ssd; }

            set { ssd = value; }

        }        

        public string Key

        {

            get { return key; }

            set { key = value; }

        }        

        public string AreaId

        {

            get { return areaId; }

            set { areaId = value; }

        }        

        public string Number

        {

            get { return number; }

            set { number = value; }

        }       

    }

}