已停止工作是什么鬼？

IMr_X 2016-03-12 08:58:46

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galiniur0u 2016-03-14

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按照楼主的程序敲了一遍（楼主好省事，也不说贴哥源码看看

），没遇到楼主说的问题，只不过结果不正确而已。

#include <stdlib.h>

#include <stdio.h>

#include <conio.h>



#define DENSITY 62.4



int main(int argc, char *argv[])

{

	double weight, volume;

	int size, letters;

	char name[40];



	printf("Hi!what's your first name?\n");

	scanf_s("%s", name, 40);

	printf("$s, what's your weight in pounds?\n", name);

	scanf_s("%f", &weight);

	size = sizeof(name);

	letters = strlen(name);

	volume = weight / DENSITY;

	printf("Well, %s, your volume is %2.2f cubic feet.\n", name, volume);

	printf("Also, your first name has %d letters.\n", letters);

	printf("and we have %d bytes to store it in.\n", size);

	getchar();

	return 0;

}

cocoabird 2016-03-14

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一行一行的打印看哪部份出问题，编译器不同，有时结果也不一样这样问也没什么意义

赵4老师 2016-03-14

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printf里面的%和变量的一一对应关系 scanf里面的%和变量以及变量前加不加&的一一对应关系是C代码中非常容易出错的地方，而且通常编译还不出错。所以在编译源代码之前值得专门仔细检查一遍甚至多遍。

#include <stdlib.h>
#include <stdio.h>

#define DENSITY 62.4

int main(int argc, char *argv[])
{
    double weight, volume;
    int size, letters;
    char name[40];

    printf("Hi!what's your first name?\n");
    scanf_s("%s", name, 40);
    printf("%s, what's your weight in pounds?\n", name);
    scanf_s("%lf", &weight);
    size = sizeof(name);
    letters = strlen(name);
    volume = weight / DENSITY;
    printf("Well, %s, your volume is %2.2lf cubic feet.\n", name, volume);
    printf("Also, your first name has %d letters.\n", letters);
    printf("and we have %d bytes to store it in.\n", size);
    getchar();
    return 0;
}