关于C语言的错误，用VS2015编写的

[xu_chenyi]

//C language program
#include<stdio.h>
#include<stdlib.h>

int main(void)
{
double number1 = 0.0;
double number2 = 0.0;
int operation = 0;
double result = 0.0;


printf("\n请在里输入要计算数字\n");
scanf("%lf %c %lf\n", &number1, &operation, number2);

switch (operation)
{
case 1:
result = number1 + number2;
printf("= %f\n", &result);
break;

case 2:
result = number1 - number2;
printf("= %f\n", &result);
break;

case 3:
result = number1 * number2;
printf("= %f\n", &result);
break;

case 4:
if (number2 == 0)
printf("\n\n数字输入错误，除数不能为0!\n");
else
result = number1 / number2;
printf("= %f\n", &result);
break;



default:
printf("不正确的操作法!!!");
break;

}

system("pause");
return 0;

}

按F5键后出现以下错误提示
Program: D:\Documents\Visual Studio 2015\Projects\TEST\Debug\TEST.exe
File: minkernel\crts\ucrt\inc\corecrt_internal_stdio_input.h
Line: 1581

Expression: result_pointer != nullptr

For information on how your program can cause an assertion
failure, see the Visual C++ documentation on asserts.

(Press Retry to debug the application)

[dustpg]

vs2015的话，应该有一大堆警告信息吧, 反正就是关于类型不安全的

[小灸舞]

1.scanf("%lf %c %lf\n", &number1, &operation, number2);这句不对 number2前面少了&，%c应该是%d吧，'\n'也要去掉 2.printf("= %f\n", &result);也不对，result前面多了&

#include<stdio.h>
#include<stdlib.h>

int main(void)
{
	double number1 = 0.0;
	double number2 = 0.0;
	int operation = 0;
	double result = 0.0;


	printf("\n请在里输入要计算数字\n");
	scanf("%lf %d %lf", &number1, &operation, &number2);

	switch (operation)
	{
	case 1:
		result = number1 + number2;
		printf("= %f\n", result);
		break;

	case 2:
		result = number1 - number2;
		printf("= %f\n", result);
		break;

	case 3:
		result = number1 * number2;
		printf("= %f\n", result);
		break;

	case 4:
		if (number2 == 0)
			printf("\n\n数字输入错误，除数不能为0!\n");
		else
			result = number1 / number2;
		printf("= %f\n", result);
		break;



	default:
		printf("不正确的操作法!!!");
		break;

	}

	system("pause");
	return 0;

}

[小灸舞]

引用 3楼我是你的主体 的回复:

按照你的指点问题已经解决，我怎么样把分给你？ 我刚自学C语言没几天，有一点不太明白： 为什么 这一句”scanf("%lf %d %lf", &number1, &operation, &number2);“要加&， 而这里”result = number1 + number2; printf("= %f\n", result);“却不能加呢？

点结帖按钮。 因为scanf是这样规定的，你可以理解成要将输入的数据写入一个内存地址，由于是地址，所以要加&

[xu_chenyi]

按照你的指点问题已经解决，我怎么样把分给你？ 我刚自学C语言没几天，有一点不太明白： 为什么 这一句”scanf("%lf %d %lf", &number1, &operation, &number2);“要加&， 而这里”result = number1 + number2; printf("= %f\n", result);“却不能加呢？