用牛顿法求x^2=10的解

#include<cstdio> #include<cmath> double f(double x) { return x-((pow(x,2)-10)/(2*x)); } int main() {double a=1,b=f(a); int i=10; while(fabs(b-a)>=1e-9) {a=b; b=f(a); printf("%.8lf\n",a); } return 0; }