c语言动态链表输出乱码

[Gnglas]

#include<stdio.h>
#include<stdlib.h>
typedef struct studens
{
	char name[20];
	int fen;
	struct studens* p;
}stu;
stu* New()
{
	stu* p1, * p2, * head;
	p1=p2 = (stu*)malloc(sizeof(stu));
	
	scanf_s("%d", &p1->fen); getchar(); fgets(p1->name, 20, stdin);
	head = p1;
	while (p1->fen != 0)
	{
		p1=(stu*)malloc(sizeof(stu));
		
		p2->p = p1;
		p2 = p1;

		scanf_s("%d", &p1->fen); getchar();
fgets(p1->name, 20, stdin);
	}
	p1= NULL;
	return head;
}
void printf_New(stu *asd)
{
	while (asd->p != NULL)
	{
		printf("%d %c\n",asd->fen,asd->name);
		asd = asd->p;	
	}
}
int main()
{
	stu* hard;
	hard = New();
	printf_New(hard);
	return 0;

	
}

[qybao]

printf("%d %c\n",asd->fen,asd->name);改成%s

[Gnglas]

引用 1 楼 qybao 的回复:

printf("%d %c\n",asd->fen,asd->name);改成%s

改成%s他会警告说printf引用字符形式

[Gnglas]

引用 1 楼 qybao 的回复:

printf("%d %c\n",asd->fen,asd->name);改成%s

好吧你是对的

[Gnglas]

引用 1 楼 qybao 的回复:

printf("%d %c\n",asd->fen,asd->name);改成%s

那愉快的结贴了

[铖邑]

引用 2 楼 Gnglas 的回复：

引用 1 楼 qybao 的回复:

printf("%d %c\n",asd->fen,asd->name);改成%s

改成%s他会警告说printf引用字符形式

什么意思？