c语言的高手请进来

[yyts]

现有一字符串"12345*67890*34567",
怎么编写代码把用"*"分隔的12345和67890和34567分别取出来并打印

[larryvc]

char * str="12345*67890*34567"

char* str1=memcpy(str,str1,5);
char* str2=memcpy(str+6,str2,5);
char* str3=memcpy(str+12,str3,5);

[JetGeng]

可以用strstr找出个各子窜的位置在用楼上的memcpy就搞定了。

[liao2001]

楼上的代码。。。空间都没
sscanf(str,"%d*%d*%d",a,b,c);

或自己一个个字符读取，用*和0做分界符

[boxban]

#include <string.h>
#include <stdio.h>

char string[] = "12345*67890*34567";
char seps[] = "*";
char *token;

void main( void )
{
printf( "%s\n\nTokens:\n", string );
/* Establish string and get the first token: */
token = strtok( string, seps );
while( token != NULL )
{
/* While there are tokens in "string" */
printf( " %s\n", token );
/* Get next token: */
token = strtok( NULL, seps );
}
}

[mahumahu]

用STL

[liansdan]

char * str="12345*67890*34567"
while(1)
{
while(*str!='*'){
printf("%c",*str++);
}
if(*str=='\0') break;
str++;
}
大致辞

[henghengpig]

#include <stdio.h>
void main()
{
printf("\n123456789034567\n");
}

[liansdan]

char * str="12345*67890*34567"
while(1)
{
while(*str!='*'){
printf("%c",*str++);
if(*str=='\0') break;
}
str++;
}
上面那个有点错，大概的内容如此吧！不是很清楚，望谅解！！！

[liansdan]

在“str++;"加上

printf("\n");更好

[Weigehoho]

while(*s)
{
if( *s!='*' )
putchar(*s++);
else if(*s=='*')
printf("\n");
else
break;

}

[roselu]

同意 larryvc() 的做法!

[Bandry]

char str[] = "12345*67890*34567";
char sep[] = "*";
char *pdest = NULL;
pdest = strstr(str, sep);
while ( pdest != NULL )
{
*pdest = '\n';
pdest = strstr(str, sep);
}
printf("%s", str);

[安安0317]

用CString 最好

[蝎子i软件]

while( *s ){
if( *s!='*' )
putchar( *s );
++s;
}

[sharkhuang]

boxban(master-dreamer) 的是标准c的做法！

[qiuzhang]

完全可用版
#include "stdio.h"
#include "string.h"
main()
{
char xyz[] = "1234*567*8910";
char *p;

p = xyz;
while(*p)
{
if(*p != '*')
{
putchar(*p);
}
else
{
printf("\n");
}
p++;
}
printf("\n");
}

[buaaaladdin]

奇怪，为什么没人用strtok，很好用的函数啊，强烈推荐。

[jxdsp]

strtok吧，通用性强些

[gy_hong]

#include <stdlib.h>
#include <string.h>
#include <iostream.h>

void main( void )
{
char str[] = "12345*67890*34567";
char *buffer = new char[strlen(str)];
long tmp;
int len=0;

tmp = atol(str);;
_ltoa(tmp, buffer, 10);
while(1)
{
cout<<buffer<<endl;
len += strlen(buffer);
if(len == strlen(str)) break;
len++;
tmp = atoi(str+len);
_itoa(tmp, buffer, 10);
}
delete buffer;

}

[ccwwbb]

qiuzhang:的程序就是啊
不必要用其他的函数