字符串数组的问题？

[nochess]

我写的函数，返回值是字符串数组。因该怎么定义？

char *[] readFile(FILE *f)
{

}

编译不通过。请指教！

[xzygod]

char* readFile(FILE* f)

[nochess]

这是字符数组，返回的是一个字符串。"abc"
我想返回字符串数组。{"abc"},{"edg"}}

[TianGuangZao]

如果你的编译器不完全符合 ANSI C 标准。
请改成如下：
char **pStrArr = malloc(2 * sizeof(char *));
=>
char **pStrArr = (char **) malloc(2 * sizeof(char *));

pStrArr[0] = malloc(4);
=>
pStrArr[0] = (char *) malloc(4);

我看你用 C++, 一般常用 new 来动态分配内存，和 malloc 道理差不多，稍改一下就好了。

[sunjx119]

C++写了个例子用到字符串数组，希望对你有所帮助。

#include <iostream>

using namespace std;

int main()
{
char *p[5];
int i=0;

for(;i<5;++i)
{
cout<<"Input NO."<<i+1<<"country:"<<endl;
p[i]=new char[20];
cin>>p[i];
}

cout<<endl<<"The five countries you have entered:\n";
for(i=0;i<5;++i)
cout<<p[i]<<endl;

return 0;
}

[etheltim]

字符串不是一个标准类型，不能直接返回，用指针吧

[TianGuangZao]

一下子说不清，写个例子说明：
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char ** fun(void)
{
char **pStrArr = malloc(2 * sizeof(char *));

pStrArr[0] = malloc(4);
pStrArr[1] = malloc(4);

strcpy(pStrArr[0], "abc");
strcpy(pStrArr[1], "edg");

return pStrArr;
}


int main()
{
char **p = fun();

printf("%s\n", p[0]);
printf("%s\n", p[1]);

free(p[0]);
free(p[1]);
free(p);

return 0;
}

[nochess]

编译错误，请看看。

Compiling...
test.cpp
e:\c\test\test.cpp(7) : error C2440: 'initializing' : cannot convert from 'void *' to 'char ** '
Conversion from 'void*' to pointer to non-'void' requires an explicit cast
e:\c\test\test.cpp(9) : error C2440: '=' : cannot convert from 'void *' to 'char *'
Conversion from 'void*' to pointer to non-'void' requires an explicit cast
e:\c\test\test.cpp(10) : error C2440: '=' : cannot convert from 'void *' to 'char *'
Conversion from 'void*' to pointer to non-'void' requires an explicit cast
Error executing cl.exe.

test.obj - 3 error(s), 0 warning(s)