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本版专家分：0
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- 蓝花 2003年4月 Java大版内专家分月排行榜第三
结帖率 100% -
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Hi,
In one of the queries, we get:
01/01/2003 10
01/03/2003 1
...
We want to show
01/01/2003 10
01/02/2003 0
01/03/2003 0
01/04/2003 1
...
Is there a way to generate all the dates, say, for one year?
Thanks.![]()
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本版专家分：1787 -
你这种还是很麻烦的，有以下几种办法
1.建一个函数，返回一年中所有日的数组,然后使用
select a ,( select b from tab where dt = e.dt ) from table( ff() ) e ;
2.建一个表,表里放一年的数据.再取出来。
how to generate pie chart hi, I have a easy question need ur help.rnrnI have a txt file which has two field, one is handset model (for example "Erisson T18"), another is test fault code(pure integer number- like 12-- which stands for different fault reason). I need read this file and then generate a pie chart for the fault codes in a certain handset.rnrnAny suggestion how to do it?rnrnBTW, I am a VB learner, please show me in detail.rnrnmany thanks welcometo2000@hotmail.com
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本版专家分：0
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- 蓝花 2003年4月 Java大版内专家分月排行榜第三
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谢谢林林.
这个办法我知道. 看看有没有高手来.
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本版专家分：0
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- 蓝花 2003年4月 Java大版内专家分月排行榜第三
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我是用这个做的
select dd
from
(
select to_date('040101','YYMMDD')+rownum -1 dd
from <any_table_with_more_than_366_rows>
where rownum < 367
)
where to_char(dd,'YY') = '04'
;
各位高手,不知有无更好的方法.
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本版专家分：0
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- 蓝花 2003年4月 Java大版内专家分月排行榜第三
-
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我是用这个做的
select dd
from
(
select to_date('040101','YYMMDD')+rownum -1 dd
from <any_table_with_more_than_366_rows>
where rownum < 367
)
where to_char(dd,'YY') = '04'
;
各位高手,不知有无更好的方法.How to generate a new secret token automatically? I used Ubuntu server 12.10 to set up a Rails application on Apache with passenger, I [i]export RAILS_ENV=production[/i] before [i]rake db:create[/i] , then when I tried to run the instance getting this runtime error:rnrn[color=#FF0000]You must set a secret token in config/initializers/secret_token.rb[/color]rnrnWell, i executed command "rake secret" and then copied the outputing serial code to secret_token.rb, but that didn't solve my problem. I also triedrnrn[color=#FF0000]$ irbrnirb(main):007:0>#SecureRandom.hex(64)[/color]rnrnAny Advice Would be Greatly Appreciated! Thank you!
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本版专家分：8852
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黄花
2005年12月 Oracle大版内专家分月排行榜第二
2005年9月 Oracle大版内专家分月排行榜第二
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- 蓝花 2005年10月 Oracle大版内专家分月排行榜第三
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sql 语句如何插入全年日期？
create table BSYEAR (d date);
insert into BSYEAR
select to_date('20030101','yyyymmdd')+rownum-1
from all_objects
where rownum <= to_char(to_date('20031231','yyyymmdd'),'ddd');
![]()
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本版专家分：29640
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- 红花 2004年8月 Oracle大版内专家分月排行榜第一
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黄花
2004年9月 Oracle大版内专家分月排行榜第二
2004年7月 Oracle大版内专家分月排行榜第二
2004年6月 Oracle大版内专家分月排行榜第二
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- 蓝花 2004年10月 Oracle大版内专家分月排行榜第三
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从第一个日期开始,转换成字符,月份循环加一,再转换成日期,和表关联查询Ambiguous Dates BackgroundnnMore than 200 companies in more than 50 countries all over the world contribute towards the success of the Merck Group. You can imagine that every day Merck Group Headquarters at Darmstadt gets loads of mail from all over the world, the layout of all the letters following the customary style of their origin. In particular, the representation of a date is often ambiguous if you do not know in what order day, month, and year are given.nnFor example, if you read 01-02-03, you do not know if that represents the first of February 1903, or 2003, or if it is the third of February 1901, or 2001. It might even be the second of March 2001, or some other permutation of the three numbers. Instead of the hyphens, there could also be slashes, backslashes, dots, commas, or no delimiters at all.nnnProblemnnYou are hired to write a program that converts dates given in an unknown format to the format of the Adjusted Calender of Merck (ACM). The latter specifies the number of days relative to November 4, 2001, an important day in Merck��s history.nnnInputnnThe first line contains the number of scenarios.nnEvery scenario contains a single date on a line by itself. A date consists of three parts: A day, a month, and a year given in any order, separated either by exactly two identical delimiters, or not separated by delimiters at all. Delimiters can be slashes ��/��, backslashes ��\��, hyphens ��-��, dots ��.��, or commas ��,��. The day and month are represented by a single digit, or by two digits, the first of which can be a leading zero. Valid years are in the range 1700 . . . 2299; either all four digits are given, or just the last two that specify the year relative to the century. In the latter case, a leading zero may be omitted.nnDates are considered illegal if no valid interpretation exists. More precisely, a date is illegal if no classification of the digits as day, month, and year results in a valid date in the range January 1, 1700, to December 31, 2299. However, you can be sure that all dates given contain 3 to 8 digits, and no other characters except for maybe the two delimiters.nnRemember that February 29 is a valid date for leap-years only. A year is a leap-year if and only if either its number is divisible by four, but not by one hundred, or if its number is divisible by four hundred. So, in particular, 2000 is a leap-year, while 1700, 1800, 1900, 2100, or 2200 are not.nnnOutputnnThe output for every scenario begins with a line containing ��Scenario #i:��, where i is the number of the scenario starting at 1.nnFor every scenario, print all possible interpretations of the given date in the format of the Adjusted Calender of Merck (ACM), each interpretation in a single line, in ascending order and with duplicates removed. If no valid interpretation exists, print a line containing Illegal date instead.nnTerminate the output for each scenario with a single blank line.nnnSample Inputnn3n1631/02/29n2001-11-03n010203nnSample OutputnnScenario #1:nIllegal datennScenario #2:n-238n-1nnScenario #3:n-109847n-109820n-109513n-109456n-109149n-109119n-73323n-73296n-72989n-72932n-72625n-72595n-36799n-36772n-36465n-36408n-36101n-36071n-274n-247n60n117n424n454n36250n36277n36584n36641n36948n36978n72774n72801n73108n73165n73472n73502
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本版专家分：0
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- 蓝花 2003年4月 Java大版内专家分月排行榜第三
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dinya2003(OK):
谢谢。
能给个具体点的例子吗?Mayan Dates DescriptionnnBackground nThe NASA has secretly built a Time machine which allows them to travel into the past. Its first application is to explore the Mayan culture. They have been able to gather some important dates from Maya monuments which are suitable for further investigation. They are now faced with a problem - they need to convert those Mayan dates to the Gregorian format, which is the only kind of input their time machine understands. nProblem nWrite a conversion program to calculate the Gregorian date, the Mayan longcount and the Mayan ritual date for a given Gregorian date or Mayan longcount. nnMayan Longcount nThe starting date, day zero, for the Mayan calendar is the 13th of August 3114 BC (before Christ). From this day zero onwards the days to a certain date are counted. One day is called K'in, 20 K'in are a Winal.18 Winal are a Tun, 20 Tun make a K'atun and 20 K'atun will form a Bak'tun. Example: 12.4.9.13.3 tells us that 12 Bak'tun, 4 K'atun, 9 Tun, 13 Winal and 3 K'in (days) have passed since August 13th 3114 BC. nnMayan Ritual Dates nThe Mayans had the solar year with 365 days, there were no leap days to correct the calendar. The year was split in 18 month with 20 days and one month with 5 days. The names of the months are the following:Pob,Wo, Sip, Sotz', Tzek, Xul, Yaxk'in, Mol, Ch'en, Yax, Sak, Keh, Mak, K'ank'in, Muwan, Pax, K'ayab,Kumk'u, Wayeb. The days of the month were numbered 1 to 19 (or 1 to 4), the last day of the month was noted as day zero of the following month (i.e. you would not write 20 Pop, but 0 Wo to note the last day of the first month, the same applies to the five day month called Wayeb, its last day 5 Wayeb is written 0 Pop).Additionally to the months and days notation there is a notation which could be compared to our weeks and weekdays. Every day is labelled by both a number in the range from 1 to 13 and one of the following 20 names: Imix, Ik', Ak'bal, K'an, Chikchan, Kimi, Manik', Lamat, Muluk, Ok, Chuwen, Eb, Ben, Ix, Men,Kib, Kaban, Etz'nab, Kawak, Ahaw. Both the numbers and the names are running in cycles, so the count will go: 1 Imix, 2 Ik', 3 Ak'bal, ... 13 Ben, 1 Ix, 2 Men. It will thus take a 260 day cycle (called the ritual year) until 1 Imix is counted again (compare Figure 1 on next page). nThe weekday and month notation are used together as in the following example: 2 Kimi (weekday) 10 Yax (day and month). The 13th of August 3114 BC has the ritual date 4 Ahaw 8 Kumk'u. nnGregorian Dates nIn our calendar we use leap days. A leap day is inserted every 4 years, except every 100 years. Overruling this a leap day will be inserted every 400 years. nIt is also important to know that there is no year 0. Accordingly, 31th of December 1 BC is followed by 1st of January AD 1. The last leap year before Christ is 1 BC (the 400 year rule applies here), the next leap year after that is AD 4.nInputnnThe first line contains the number of scenarios. nFor each scenario, there is one line containing either a Mayan longcount or a Gregorian date in the following formats: nA Mayan longcount consists of 5 non-negative integers separated by dots. nA Gregorian date consists first of three integers d, m, and y, separated by slashes, and satisfying 1 <= d <= 31, 1 <= m <= 12, and 0 < y. The values may or may not be zero padded, but will never exceed two characters for d and m, and four for y. This representation is always followed by a single blank and either "BC" or "AD".nnWe will neither ask for dates preceding August 13th 3114 BC, nor for dates after 13.0.0.0.0 which is the last day in the Mayan longcount calendar. Also, you will never be given invalid dates in either calendar.nOutputnnThe output for every scenario begins with a line containing "Scenario #i:", where i is the number of the scenario starting at 1. Then, regardless of the format given in the input, three lines have to be printed representing the given date in the following order: n1. the Gregorian date in the same format as specified in the input description, but without any padding zeros; n2. the Mayan longcount representation of the date, also as described before; n3. the Mayan ritual date consisting of four parts separated by single blanks: the weekday notation with its number and name, then the day of the month followed by the name of the month. nAfter these three lines, always a blank line must be printed.nSample Inputnn2n13/08/3114 BCn12.19.10.6.14nSample OutputnnScenario #1:n13/8/3114 BCn0.0.0.0.0n4 Ahaw 8 Kumk'unnScenario #2:n28/6/2003 ADn12.19.10.6.14n9 Ix 2 Tzek
- year ( today ( )) - year(birthday)
- <em>year</em> ( today ( )) - <em>year</em>(birthday)rn在数据窗口中增加一个计算字段，内容如上，不可以为什么
- how to work with crystal report in sap business one
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- 急急,有关systemtime的时间进行加减操作，如加one day，one week ，one month，one year问题。
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- (sorry,i can't used chinese now)rnrni tried to use the service sample(all <em>generate</em>d by .NET web servicernwizard)...like the follow:rnrn [WebMethod]rn public string HelloWorld()rn rn return "Hello World";rn rnrnrnbut when i type the follow command to test the .NET service:rnhttp://localhost/WebService1/Service1.asmx?WSDLrnrnit shows error, and the error message at the follow:rnrnServer Application UnavailablernThe web application you are attempting to access on this web server isrncurrently unavailable. Please hit the "Refresh" button in your web browserrnto retry your request.rnrnAdministrator Note: An error message detailing the cause of this specificrnrequest failure can be found in the system event log of the web server.rnPlease review this log entry to discover what caused this error to occur.rnrnrnrnand when i checked the event viewer,it shows two error message:rnrn1->>aspnet_wp.exe could not be started. HRESULT for the failure: 80004005rnrn2->>aspnet_wp.exe could not be launched because the username and/or passwordrnsupplied in the processModel section of the config file are invalid.rnrnrnrnhow about your suggestion? how can i resolve it?~~~hope you can help me..:)rnrnrn--rnBenny NgrnrnBenny_Wufree@hotmail.comrnrn
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- To prepare for programming contests or coding examinations, the judge sometimes has to <em>generate</em> random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) from O (o in uppercase). One solution is to replace 1 (one) by @, 0 (zero) by %, l by L, and O by o. Now it is your job to write a program to check the accounts <em>generate</em>d by the judge, and to help the juge modify the confusing passwords.nnInputnThere are multiple test cases. Each case contains a positive integer N (nnSample Input:n2nTeam000001 R1spOdfanTeam000002 Rlsp0dfan1nteam110 abcdefg332n0nSample Output:n2nTeam000001 R@spodfanTeam000002 RLsp%dfanNo account is modified.
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我们是很有底线的