程序的输出为什么是这样？

[ThinkInDelphi]

#include "string.h"
#include "stdio.h"
static char* fullpath;
int main(int argc, char* argv[])
{ char *part="second";

fullpath=(char*)malloc(100);
fullpath="first";
//printf("%s\n",part);
printf("%s\n",fullpath);
getchar();

strcat(fullpath,part);
printf("%s\n",fullpath);
getchar();
return 0;
}输出为
first
d
如果我把//去掉，输出正常：
second
first
firstsecond
为什么呢？

[healer_kx]

fullpath=(char*)malloc(100);
fullpath="first";

这两句就非常不妥。

strncpy(fullpath, "first", strlen("first"));

[megaboy]

fullpath="first";
------------------
字符串常量是一个地址，你这样是把一个地址赋予fullpath，fullpath原来的值被抛弃了，内存泄露。再运行strcat(fullpath,part);时，由于fullpath指向一个字符串常量，再链接一个字符串，越界。把fullpath="first"改成这样：

strcpy(fullpath, "first");

[sanhill]

fullpath=(char*)malloc(100);
fullpath="first";
－－－－－－－－－－－－－－－－
代码不对，内存泄漏！可改为
fullpath=(char*)malloc(100);
strcpy（fullpath，"first"）;

[kobefly]

static char* fullpath;
int main(int argc, char* argv[])
{ char *part="second";

fullpath=(char*)malloc(100);
strcpy(fullpath, "fisrt");//fullpath="first";

here, 你的赋值方式不对,你fullpath="first";是将指针fullpath指向了常量字符串"first";
//printf("%s\n",part);
printf("%s\n",fullpath);
getchar();

strcat(fullpath,part);
printf("%s\n",fullpath);
getchar();
return 0;
}

[kobefly]

oh

sorry
已经都有人说了

[ThinkInDelphi]

谢谢大家!
megaboy的回答如此闪光~呵

[Tycool]

没有咱闪光的机会了 :-)