一个简单的socket问题 大家帮忙看看

[chenxiaochen]

我写了一个简单的用socket通信的程序 可是 在accept函数这里总是过不去 我还如何解决呢？
SOCKET s=accept(m_hSocket,(LPSOCKADDR)&m_addr,(int*)sizeof(m_addr));这是我的那个函数

各位大虾 帮帮忙了

[konj]

struct sockaddr_in ServerSocketAddr;
　　int addrlen;
　　addrlen=sizeof(ServerSocketAddr);
　　ServerSocket=accept(ListenSocket,(struct sockaddr *)&ServerSocketAddr,&addrlen);

[fyx010641]

去MSDN看看吧 数据类型错！！

[「已注销」]

ListenSocket=socket(....);
bind(ListenSocket);
.........
sockaddr_in server_addr;
int rlen=sizeof(server);
ServerSocket=accept(ListenSocket,(sockaddr *)&server,&rlen);

[Hylas]

上面已经是标准答案了；
我批示

[quanbaoxiao]

SOCKET s=accept(m_hSocket,(LPSOCKADDR)&m_addr,(int)sizeof(m_addr));

[playcats]

s
[in] A descriptor identifying a socket that has been placed in a listening state with the listen function. The connection will actually be made with the socket that is returned by accept.
addr
[out] An optional pointer to a buffer that receives the address of the connecting entity, as known to the communications layer. The exact format of the addr parameter is determined by the address family established when the socket was created.
addrlen
[out] An optional pointer to an integer that contains the length of the address addr.


1. (int*)sizeof(m_addr)):写法肯定有问题，把sizeof(m_addr)强制转化为(int*),如果sizeof(m_addr)=10，那么(int*)sizeof(m_addr))指向的内存地址为10，这应该不是正确的数据段所在的位置。应该使用&，而不是*；
2. 其中addr与addrlen是输出的，所以肯定不能是const,临时变量sizeof(m_addr)肯定不行。

[chenxiaochen]

谢谢 各位 已经解决了